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Anettt [7]
3 years ago
5

What is the simplest form of x^4 y^7 / 3 square root x^10 y^4

Mathematics
1 answer:
True [87]3 years ago
4 0
X ^ 14 y ^ 11 / square root of 3
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Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
3 years ago
What is the mean absolute deviation for the data set? {10, 15, 18, 20, 24}
Arlecino [84]

Answer:

3.92

To find the mean absolute deviation of the data, start by finding the mean of the data set.

Find the sum of the data values, and divide the sum by the number of data values.

Find the absolute value of the difference between each data value and the mean: |data value – mean|.

Find the sum of the absolute values of the differences.

Divide the sum of the absolute values of the differences by the number of data values.

7 0
3 years ago
Read 2 more answers
Database about trees include a height field. What kind of sort would list the data from tallest to shortest?
Inga [223]
Correct answer : 2) descending sort
8 0
3 years ago
Ron finds 9 books at a bookstore that he would like to buy, but he can afford only 5 of them. In how many ways can he make his s
pashok25 [27]

Answer:

15,120 for the first question. 1,680 if one of the books is a must

Step-by-step explanation:

When Ron chooses his first book, he has 9 options. After that, when he chooses his second book, he only has 8 choices because he already picked one of them. By his third choice, he only has 7 choices and so on.

We can make an equation to represent this,

9 x 8 x 7 x 6 x 5

Multiplying all of that out gets you 15,120.

The second problem is even easier. Since one of the books is already chosen for him, he starts off only having 8 options. Since he is only choosing four books this time, we are only multiplying four numbers.

8 x 7 x 6 x 5

Multiplying all of that out tells you there are 1,680 ways he can make his selection in the second scenario.

5 0
3 years ago
This month
Rudik [331]
11%= 0.11 and 8%= 0.08

0.11 x 67,530=7,428.3
0.08 x 85,740 = 6,859.2
 so person A made more than person b
6 0
3 years ago
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