Answer:
Therefore, the probability is P=1/84.
Step-by-step explanation:
We have a bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty.
We conclude that in a bag have 9 tokens.
We calculate the probability that the red tokens are drawn consecutively.
We calculate the number of possible combinations:
Number of favorable combinations is 1.
Therefore, the probability is P=1/84.
The probability that the cube never lands on 3 is (D) 23.3%.
<h3>
What is probability?</h3>
- A probability formula can be used to calculate the likelihood of an occurrence by simply dividing the favorable number of possibilities by the entire number of possible outcomes.
To find the probability that the cube never lands on 3:
Given -
Required
- Probability of not landing on 3.
First, we need to get the probability of landing on 3 in a single toss.
For a number cube,
- n(3) = 1 and n(total) = 6
So, the probability is P(3) = 1/6
First, we need to get the probability of not landing on 3 in a single toss.
Opposite probability = 1.
Make P(3') the subject of the formula.
- P(3') = 1 - P(3)
- P(3') = 1 - 1/6
- P(3') = 5/6
In 8 toss, the required probability is (P(3'))⁸
This gives:
- P = (5/6)⁸
- P = 390625/1679616
- P = 0.23256803936
Approximate to 1 decimal place, P = 23.3%.
Therefore, the probability that the cube never lands on 3 is (D) 23.3%.
Know more about probability here:
brainly.com/question/25870256
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The correct question is given below:
A number cube is tossed 8 times. What is the probability that the cube never lands on 3?
A. 6.0%
B. 10.4%
C. 16.7%
D. 23.3%
<span>2x + x = 12
=> x =12/3 =4
so, original number is 84.</span>
Answer:
0
Step-by-step explanation:
The only possible outcomes on the die are 1,2,3,4,5,6.
Since 7 is not in the possible outcome list, It is impossible to obtain a 7 on this 6-sided die.
If the question <em>had </em>asked for the probability of other values, it would have been 1/6, because you can get each number at least once every 6 rolls. This, however varies in terms of experimental probability
Hope this helps
Answer:
(a)
(b)$2
Step-by-step explanation:
In the given game of rolling a die. these are the possible winnings.
- If the number showing is even(2, 4, or 6) or 1, you win $3.
- If the number showing is either 3 or 5 you win $0.
There are 6 sides in the die.
(i)The probability distribution of x.
Let x be the amount won
Therefore:
Probability distribution of x.
(ii) Expected amount of dollar won
Expected Amount
You would expect to win $2.
