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Tcecarenko [31]
3 years ago
8

Ik I said one more buh I assure u this is the last :p

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
3 0
Here you go this took me time

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Estimate the value of the function at x = 2. Can someone help me with this?
Zielflug [23.3K]

Answer:

y ≈ 2.1

Step-by-step explanation:

If you look at the graph and locate on the x axis 2, you can see that directly above on the line is a little more than 2.

7 0
3 years ago
Jobi is taking his children on a long drive. Jobi is making snack bags to take on the drive using 40 granola bars and 32 apples.
Karolina [17]
40
40 \times 32
8 0
3 years ago
Suppose that among all U.S. Students, 80% have gone to an amusement park and 45% have gone to a beach. Only 15% have done neithe
valentinak56 [21]

Answer:

5%

Step-by-step explanation:

Let x represent the percentage of people that have gone to both the park and the beach.

The percentage of people that have gone only to the amusement park = 80% - x% = 80 - x

The percentage of people that have gone only to the beach = 45% - x% = 45 - x

Therefore:

100% = (80 - x) + (45 - x) + (x) + (15)

100 = 80 + 45 + 15 -x - x + x

100 = 140 - x

x = 140 - 100

x = 40%

Therefore 40% of the students have gone to both the park and the beach.

The probability that the student has gone to the beach but not to an amusement park = 45% - 40% = 5%

5 0
2 years ago
Pls help me asap... plssss..... ty​
olasank [31]

Answer:

Well... "Alphabets" in math, are defined as variables...

And we use variables to show the things that we are multiplying, dividing, subtracting, or adding. Like: Beach balls=B "Tommy has to blow up 20 beach balls before he can go to the beach, his mom offers to help him. How many beach balls do each of them have to blow up?" One equation we could use is "B/2 or B divided by 2" :)

Step-by-step explanation:

5 0
2 years ago
PLEASE HELP ME! I really need help y'all...
ikadub [295]

just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)

\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill

8 0
3 years ago
Read 2 more answers
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