All categories

3 years ago

Which point lies on a sphere? J B S

Mathematics

2 answers:

Mashcka [7]3 years ago

6 0

Answer:

<h2>Point B lies on a sphere.</h2>

Step-by-step explanation:

Remember, a sphere is defined as a three-dimensional object where all points on its surface are equidistant form its center.

According to its definition, all point on the boundaries can be called a point on the sphere.

So, among the options, only point B is on the sphere, because J and S are inside.

Therefore, the right answer is Point B.

iren [92.7K]3 years ago

3 0

Is letter B
Because the sphere means the outside part of the sphere, not inside of it

You might be interested in

A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a ne

Evgen [1.6K]

Answer:

a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between 0.6290 and 0.6948.

b. If the sample size is changed, the confidence interval changes as the standard error depends on sample size.

About 90% percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about 10% percent will not contain the true population proportion.

Step-by-step explanation:

We have to calculate a 90% confidence interval for the proportion.

The sample proportion is p=0.6619.

$p=X/n=370/559=0.6619$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.6619*0.3381}{559}}\\\\\\ \sigma_p=\sqrt{0.0004}=0.02$

The critical z-value for a 90% confidence interval is z=1.6449.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_p=1.6449 \cdot 0.02=0.0329$

Then, the lower and upper bounds of the confidence interval are:

$LL=p-z \cdot \sigma_p = 0.6619-0.0329=0.6290\\\\UL=p+z \cdot \sigma_p = 0.6619+0.0329=0.6948$

The 90% confidence interval for the population proportion is (0.6290, 0.6948).

3 0

3 years ago

Write the number 270 as a sum of three numbers so that the sum of the products taken two at a time is a maximum. (Enter the thre

iren [92.7K]

Answer:

x=y=z=90.

Step-by-step explanation:

let the 3 numbers be x,y,z.

let s be sum

s=x+y+z

we need to maximize xy+yz+zx

or , xy + y(270-(x+y))+x(270-(x+y)) = P(x)

Use Lagrange's Multipliers

⇒ΔP= λΔS

⇒ $\frac{x+y}{x+z} =1$

⇒y=x

⇒\frac{x+z}{x+y} =1

⇒z=y

⇒x=y=z

⇒3x = 270

⇒x= 90

hence, x=y=z=90.

3 0

3 years ago

A spinner is divided into four equal sections. Which situation can be represented using this simulation?

snow_lady [41]

Answer:

A. picking a red rose from a vase with two red, two pink, two yellow, and two white roses

Step-by-step explanation:

please mark this answer as brainlest

4 0

3 years ago

•225+225 = ?<br>•5/25 = ?<br>•78-8 = ?<br>•13*1 = ?

Karolina [17]

ANSWER:

[i] 225 + 225 = 450.

[ii] 5/25 = 1/5.

[iii] 78 - 8 = 70.

[iv] 13 × 1 = 13.

5 0

3 years ago

Read 2 more answers

Please answer 26 and 27 please thank you

ser-zykov [4K]

Answer:

Part 26) $3\frac{1}{4}\ in$

Part 27) $2\frac{2}{3}\ cups$

Step-by-step explanation:

Part 26)

we know that

The length of Alana's hair was 9 3/4 inches

After her haircut, the length was 6 1/2 inches

To find out how many inches did she have cut subtract 6 1/2 from 9 3/4

but first

Convert mixed number to an improper fraction

$9\frac{3}{4}\ in=\frac{9*4+3}{4}=\frac{39}{4}\ in$

$6\frac{1}{2}\ in=\frac{6*2+1}{2}=\frac{13}{2}\ in$

Find the difference

$\frac{39}{4}-\frac{13}{2}=\frac{39-26}{4}=\frac{13}{4}\ in$

Convert to mixed number

$\frac{13}{4}\ in=\frac{12}{4}+\frac{1}{4}=3\frac{1}{4}\ in$

Part 27)

we have that

Emeril used a total of 7 1/4 cups of flour to make three pastries

He used 2 1/4 cup of flour for the first and 2 1/3 cups of flour for the second

To find out how much cups of flour Emeril use for the third pastry, subtract the sum of the cups of flour used in the first and second pastry from the total cups of pastry used

Let

x ----> number of cups of flour used in the third pastry

$x=7\frac{1}{4}-(2\frac{1}{4} +2\frac{1}{3})$