Answer:
-x² + 12x + 3
Step-by-step explanation:
Step 1: Write expression
5x² + 9x + 3 - (6x² - 3x)
Step 2: Distribute
5x² + 9x + 3 - 6x² + 3x
Step 3: Combine like terms
-x² + 12x + 3
Answer:
The mentioned number in the exercise is:
Step-by-step explanation:
To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.
If:
- x = hundredths digit
- y = tens digit
- z = ones digit
We can write:
- x = z + 1 (the hundreds digit is one more than the ones digit).
- y = 2x (the tens digit is twice the hundreds digit).
- x + y + z = 11 (the sum of the digits is 11).
Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:
- x + y + z = 11
- (z + 1) + y + z = 11 (remember x = z + 1)
- z + 1 + y + z = 11
- z + z +y + 1 = 11 (we just ordered the equation)
- 2z + y + 1 = 11 (z + z = 2z)
- 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
- 2z + y = 10
- 2z + (2x) = 10 (remember y = 2x)
- 2z + 2x = 10
- 2z + 2(z + 1) = 10 (x = z + 1 again)
- 2z + 2z + 2 = 10
- 4z + 2 = 10
- 4z = 10 - 2
- 4z = 8
- z = 8/4
- <u>z = 2</u>
Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:
- x = z + 1
- x = 2 + 1
- <u>x = 3</u>
And we'll use the second equation to obtain the value of y (the tens digit):
- y = 2x
- y = 2(3)
- <u>y = 6</u>
Organizing the digits, we obtain the number:
- Number = xyz
- <u>Number = 362</u>
As you can see, <em><u>the obtained number is 362</u></em>.
Answer:
x(x+7)
Step-by-step explanation:
x^2+4x+3x
Combine like terms
x^2+7x
Factor out an x
x(x+7)
9514 1404 393
Answer:
p : q = 3 : 2
Step-by-step explanation:
You are given sufficient information to write two relations involving p and q. We presume these will be sufficient to find an answer to the question. We will be able to find p and q. Then we can find their ratio, as the problem asks.
(p-15)/(q-15) = 2/1
(p+30)/(q+30) = 5/4
__
From the first equation, we get ...
p -15 = 2(q -15)
p = 2q -15 . . . . . . . add 15, simplify
From the second equation, we get ...
4(p +30) = 5(q +30)
4p + 120 = 5q + 150
4p = 5q + 30
Using the first equation to substitute for p, we have ...
4(2q -15) = 5q +30
8q -60 = 5q +30 . . . eliminate parentheses
3q = 90 . . . . . . . . . . . add 60-5q to both sides
q = 30 . . . . . . . . . . . . divide by 3
p = 2q -15 = 2(30) -15 = 45
Then the desired ratio is ...
p : q = 45 : 30
p : q = 3 : 2