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Alexeev081 [22]
3 years ago
13

What is the area of a square with the length of a side equaling 3a^5???

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:


Step-by-step explanation:

Yes it is

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Bill wants to post three parcels.
ad-work [718]
The answer should be £6.70
3 0
3 years ago
You have quarters and dimes that total $2.80. your friends says its possible that the number of quarters is 8 more than the numb
Sidana [21]

\text{Let the number of dimes be x, then as per the friend the number of }\\
\text{quarters should be 8 more than dimes, so number of quarters}=x+8\\
\\
\text{we know that the value of 1 dime is }\$ 0.10 \text{ value of one quarter is }\$0.25\\
\\
\text{And since the total value of quarters and dimes is }\$2.80, \text{ so we have}\\
\\
0.10(x)+0.25(x+8)=2.80\\
\\
\Rightarrow 0.10x+0.25x+2=2.80\\
\\
\Rightarrow 0.35x=2.80-2\\
\\
\Rightarrow 0.35x=0.80

\Rightarrow x=\frac{0.80}{0.35}=2.29\\
\\
\text{so if we take 2 dimes then we'll have to take 10 quarters according to friend.}\\
\\
\text{So the statement of friend is } WRONG

6 0
3 years ago
If y varies jointly as x and the cube of z and y=16 when x=4 and z=2 then y=0.5 when x=-8 and z=-3?
Evgesh-ka [11]

Answer: F (False)

Step-by-step explanation:

 Jointly variation has the following form:

y=kxz

Where k is a constant of propotionality.

Substitute values:

If y=16, x=4 and z=2, then k is:

16=k(4)(2)^{3}\\k=1/2

If x=-8 and z=-3 the the value of y is:

y=(1/2)(-8)(-3)^{3}\\y=-108

Then the answer is FALSE.

8 0
4 years ago
Read 2 more answers
A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\

\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
4 years ago
Whats 4x=28? whats the x for the answer?
Alik [6]
76 is the answer for x.
5 0
3 years ago
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