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Pepsi [2]
2 years ago
11

where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

tself
Mathematics
1 answer:
irina [24]2 years ago
5 0

Answer:

An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to  reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.

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Which of the following expression is equal to x^2+25?
nignag [31]
A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2


B: (x - 5i)^2
= (x  +   - 5i)(x +  - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2


C: (x - 5i)(x + 5i)
= (x +  - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2


D: (x + 10i)(x  - 15i)
= (x + 10i)(x +  - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
=  - 150i^2 + 5ix + x^2



Hope that helps!!!

6 0
3 years ago
Read 2 more answers
Plz help me plz I need answer and explanation plz
pentagon [3]

9514 1404 393

Answer:

  A = {put, the, cake, in, basket}

  B = {is, the, cake, in, basket}

  C = {no, the, cake, in, basket}

  D = { }

Step-by-step explanation:

A = (A -B) ∪ (A∩B) ∪ (A∩C}

A = {put} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

A = {put, the, cake, in, basket}

__

B = (B -A) ∪ (B -C) ∪ (B∩A) ∪ (B∩C)

B = {is} ∪ {is} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

B = {is, the, cake, in, basket}

__

C = (C -B) ∪ (C∩A) ∪ (C∩B)

C = {no} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

C = {no, the, cake, in, basket}

__

D = { } . . . . not defined anywhere

8 0
3 years ago
Use prime factorization to reduce the fraction 36/180
laila [671]

Answer:

Step-by-step explanation:

36 = 6* 6 = 2* 3 * 2* 3 = 2*2*3*3

180 = 2 * 2 * 3 * 3 * 5 = 2 * 2 * 3*3*5

\frac{36}{180}= \frac{2*2*3*3}{2*2*3*3*5} =  \frac{1}{5}

Factors that are common will be cancelled

5 0
2 years ago
Please help me find this, it's urgent!
Dafna11 [192]
The slope is 2/1 and tye y intercept is 2
4 0
3 years ago
If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc
grin007 [14]

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112

3 0
3 years ago
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