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Pepsi [2]
3 years ago
11

where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

tself
Mathematics
1 answer:
irina [24]3 years ago
5 0

Answer:

An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to  reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.

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How many 'faces' are on this square pyramid?​
qaws [65]

Answer:

5

Step-by-step explanation:

There are 5 faces on a square pyramid

7 0
3 years ago
Please help! Sketch the graph of each line.
madam [21]

Answer:

1) (-3,0) (0,-3)

2) (-2,0)

3) (5,0) (0,-1)

4) (12,0) (0,3)

5) (-16,0) (0,4)

6) (-0.8333,0) (0,5)

4 0
3 years ago
What is true regarding two adjacent arcs created by two<br> intersecting diameters?
Juli2301 [7.4K]

Given:

Two diameters intersect each other.

To find:

The correct statement regarding two adjacent arcs created by two  intersecting diameters.

Solution:

We know that, two diameter intersect each other at origin and measure of arc is equal to the corresponding angle generated by the intersection of diameters.

If two lines intersect each other then we get 4 angles and sum of any two adjacent angles is 180°.

It means the sum of any two adjacent central angles generated by the intersection of diameters is 180°.

So, the sum of two adjacent arcs created by two  intersecting diameters is 180°.

Therefore, the correct option is C.

7 0
3 years ago
6. The variable x and y vary directly, and y = 40 when x = 5. Which equation relates the variables?
valkas [14]

Answer:

The equation relates the variables is y = 8x ⇒ D

Step-by-step explanation:

If x and y vary directly (y ∝ x), then y = k x, where

  • k is the constant of variation
  • k can be found using the initial value of x and y

∵ The variable x and y vary directly

∴ y ∝ x

→ By using the rule above

∴ y = k x

∵ y = 40 when x = 5

∴ The initial values of x and y are x = 5 and y = 40

→ Substitute them in the equation above to find k

∵ 40 = k(5)

∴ 40 = 5k

→ Divide both sides by 5

∵ \frac{40}{5} = \frac{5k}{5}

∴ 8 = k

→ Substitute the value of k in the equation above

∴ y = 8x

∴ The equation relates the variables is y = 8x

5 0
3 years ago
What goes in the space? (3x − ...)2 = 9x2−6x+1<br> I will give points and brainliest!
Crazy boy [7]

{(x - y)}^{2}  =  {x}^{2}  - 2xy +  {y}^{2}

(3x - ...)^{2}  = 9 {x}^{2}  - 6x + 1 \\  {(3x - 1)}^{2}  = 9 {x}^{2}  -6x + 1

6 0
4 years ago
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