Yeah you should try khan academy or Ytube
f(x)=2x^2+0x-5
Find the vertex
0/4=0=x
Input x into the equation to find y or f(x)
0+0-5=f(x)
(0,-5) = Vertex
Now find a random x coordinate to input into the equation.
Let's do 4.
32+0-5=f(x)=27
It may not look like a parabola due to it being uneven.
Answer:
The equation of the line is y = 3/2x + 5/2
Step-by-step explanation:
To find the equation of this line, start by using the two points with the slope formula to find the slope.
m(slope) = (y2 - y1)/(x2 - x1)
m = (4 - 1)/(1 - -1)
m = 3/(1 + 1)
m = 3/2
Now that we have the slope, we can use that and either point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 4 = 3/2(x - 1)
y - 4 = 3/2x - 3/2
y = 3/2x + 5/2
Answer:
answer is b
Step-by-step explanation:
look at the picture