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3 years ago

What is the value of y in the equation? 1.5y + 3 = -1.5

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

Answer:

y = -3

Step-by-step explanation:

1.5y + 3 = -1.5

When doing algebraic equations, you are always doing PEMDAS backwards.

First, subtract:

1.5y = -4.5

Then divide:

y = -3

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Combine Like terms: 9x + 3x + 4 + 6 *

liq [111]

Answer:

12x+10

Step-by-step explanation:

9x+3x=12x

and

4+6=10

4 0

3 years ago

Rearrange then factorise x^2-5x+19=5x+3

Tema [17]

Answer:

x = ±4i or x = ±√-16

Step-by-step explanation:

x² - 5x + 19 = 5x + 3

x² + 16 = 0

x² = -16

x = ±√-16 (a negative square root is an imaginary number)

4 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

How do you solve this whole thing please?

NemiM [27]

Answer:

Step-by-step explanation:

Let's look at the first two, and hopefully you'll be able to figure the rest out:

1. Answer below

$d = rt$

The problem asks us to solve for $r$ , so that means we need to get $r$ on one side of the equation by itself. To do so, we will need to divide both sides of the equation by $t$ :

$\frac{d}{t} = \frac{rt}{t}$

$\frac{d}{t} = r$

2. Answer below

$B = T - Lc$

The problem asks us to solve for $T$ , so that means we need to get $T$ on one side of the equation by itself. To do so, we will need to add $Lc$ to both sides of equation:

$B + Lc = T - Lc + Lc$

$B + Lc = T$

7 0

4 years ago

Jake says he can run of a mile in of an hour. How fast is this in miles per hour?

UNO [17]

Well according to your question you want to know his miles per hour ratio right well if hes olny running one mile the ratio would be a 1:1. thats one mile per hour, hes a slow runner :/

8 0

3 years ago