If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
Answer:
See below
Step-by-step explanation:
The function 
oscillates between -1 and 1, so the range is 
.
The most reasonable answer would be 2 meters since two meters equals about 6 feet.
Answer:
144x^2−y^2−169 because ther are no like terms
Step-by-step explanation:
23,307,609 that is the answer
