Question

Jason is buying hamburgers and hot dogs for a barbecue. One package of hamburgers costs $10. One package of hotdogs costs $5. He has $60 to spend, and must buy AT LEAST 3 packages of hot dogs.
What 2 inequalities can be used?

Answer 1

Let hotdogs be d and hamburgers be b

he needs AT LEAST 3 packages of hotdogs
so
$d \geqslant 3$
each packet costs $5 so he must spend $15 in total on hotdogs
so he can spend NO MORE than $45 on hamburgers so can buy no more than 4 packs of hamburgers
so
$b \leqslant 4$

Answer 2

Answer:

10x + 5y ≤ 60 & y ≥ 3

Step-by-step explanation:

Let x = the number of hamburgers

Let y = the number of hotdogs

Let us first represent the amount of food:

10x + 5y ≤ 60

This means x packages of $10 hamburgers plus y packages of $5 hotdogs is greater than or equal to $60.

However, we have also been given another important piece of information and that is that he must buy at least three packages of hotdogs.

y ≥ 3

this means that the packages of hotdogs must be no less than 3.

Hence or two inequalities are 10x + 5y ≤ 60 & y ≥ 3.

This also means that the least he can spend on hotdogs is $15. The most he can spend on hamburgers is $45, meaning the most packages of hamburgers he can get is 4

PLEASE MARK BRAINLIEST