Answer:
Chemical potential energy is the energy stored in the chemical bonds of a substance. The various chemicals that make up gasoline contain a large amount of chemical potential energy that is released when the gasoline is burned in a controlled way in the engine of the car. The release of that energy does two things
Explanation:
The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
Answer:
n = 3
Solution:
Since, the slit used is same and hence slit distance 'x' will also be same.
Also, the wavelengths coincide, will also be same.
Using Bragg's eqn for both the wavelengths:
(1)
(2)
equate eqn (1) and (2):
n = 3
There is no displacement. The frog is back where it began.
Here volume of gas is not given so question is solved assuming volume as 1 L.
The number of moles of 1 L gas present in the sealed container at a
pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.
The ideal gas law equation can be written as
PV = nR T
Here
P is the pressure of the gas in atm
V is the volume it occupies in L
n is the number of moles of gas present in the sample
R is the universal gas constant, equal to 0.0821 atm L/ mol K
T is the absolute temperature of the gas in Kelvin
Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.
So
P = 125 kPa
1 atm = 760 kPa
P = 125/760 = 0.1644 atm
T = 25 degree celsius = 25 +273 = 298 K
Taking V = 1 L
So
n = PV/RT
n = 0.1644 x 1 / 0.0821 x 298
n = 0.0067 moles
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Answer:
2.76×10⁻¹⁰ C
Explanation:
Applying,
V = W/q................... Equation 1
Where V = Electric Potential, E = Electric potential energy, q = charge.
make q the subject of the equation
q = W/V................ Equation 2
From the question,
Given: W = 4.26×10⁻⁸ J, V = 154.5 V
Substitute these values into equation 2
q = 4.26×10⁻⁸/154.5
q = 2.76×10⁻¹⁰ C