Ask question

Ask question

All categories

gizmo_the_mogwai [7]

2 years ago

7

Why are road accidents at high speeds very much worse than road accidents at low speeds?

2 answers:

Marina86 [1]2 years ago

7 0

Vehicles with high speeds have high momenta (plural of momentum). When they come to rest in very small time they experience high forces
we know that rate of change of momentum is force, lower the time higher is force. So, slow moving vehicles experience less force. It is important to note that if any one vehicle involving has high speed it can do more damage both the vehicles involving.

Triss [41]2 years ago

4 0

Answer:

The momentum makes it worse.

Explanation:

The momentum of vehicles running at faster speeds is very high and causes a lot of damage to the vehicles.

You might be interested in

Where are the magnetic fields strongest near a bar magnet?

KatRina [158]

The answer is near the poles.

3 0

2 years ago

Read 2 more answers

What is the correct equation to use to calculate the resultant force for the below inclined plane Freebody diagram?

ra1l [238]

Answer:

b.mgcos

Explanation:

..............

7 0

2 years ago

What are glacial episodes example of

il63 [147K]

Glacial episodes are examples of positive feedbacks

6 0

2 years ago

Read 2 more answers

The speed of a certain proton is 350 km/s. If the uncertainty in its momentum is 0.100%, what is the necessary uncertainty in it

Evgesh-ka [11]

Answer:

$\Delta x = 1.807 \times 10^{-10}m$

Explanation:

mass of proton, m = 1.67 x 10^-27 kg

speed of proton, v = 350 km/s = 350,000 m/s

Momentum of proton, p = mass x speed

p = 1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s

uncertainty in momentum, Δp = 0.1 % of p

Δp = $\frac{0.1\times 5.845 \times 10^{-22}}{100}=5.845 \times 10^{-25}$

According to the principle

$\Delta x\times \Delta p \geq \frac{h}{2\pi }$

where, Δx be the uncertainty in position

$\Delta x\times 5.845 \times 10^{-25}= \frac{6.634 \times 10^{-34}}{2\times 3.14}$

$\Delta x = 1.807 \times 10^{-10}m$

5 0

2 years ago

The shortest distance from start to finish is called three vector addition

Jlenok [28]

Answer:

False

Explanation:

The shortest distance between the starting point and the finishing point is called the Displacement. This is a vector quantity

It is obtained by subtracting the components of staring point from the components of finishing point

$\overrightarrow{AB} = \overrightarrow{OB} - \overrightarrow{OA}$

It can be expressed in terms of the components in three dimensional space.

Ex.

$3 \overrightarrow{i} + 4 \overrightarrow{j}- 8 \overrightarrow{k}$

8 0

3 years ago