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gizmo_the_mogwai [7]
3 years ago
7

Why are road accidents at high speeds very much worse than road accidents at low speeds?

Physics
2 answers:
Marina86 [1]3 years ago
7 0
Vehicles with high speeds have high momenta (plural of momentum). When they come to rest in very small time they experience high forces
we know that rate of change of momentum is force, lower the time higher is force. So, slow moving vehicles experience less force. It is important to note that if any one vehicle involving has high speed it can do more damage both the vehicles involving.
Triss [41]3 years ago
4 0

Answer:

The momentum makes it worse.

Explanation:

The momentum of vehicles running at faster speeds is very high and causes a lot of damage to the vehicles.

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olga_2 [115]
<span>D. Mass equals weight times acceleration due to gravity.


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3 years ago
Why are mercury and the earths moon so cratered?
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They are cratered because of meteoroids, neither of them have an atmosphere to disintegrate the meteors, and neither of them have water to erode the craters.
8 0
3 years ago
g Vector has a magnitude of 10.9 units and points due west. Vector points due north. (a) What is the magnitude of if + has a mag
NARA [144]

Answer:

a. 11.3 units

b. 46.031°

c. 11.3 units

d. 46.03°

Explanation:

a. magnitude

B = \sqrt{R^{2}-A^{2}  }

= √15.7² - 10.9²

= √127.68

= 11.3 units

b. direction

θ = cos⁻¹(10.9units/15.7 units)

= 46.031⁰ north of west

c. thge magnitude at 15.7 units is the same as solution a above

15.7² = 10.9² + B²

B = 11.3 units.

d. the direction is same as  answer b.

θ = 46.031°

but the vector faces south of west

3 0
3 years ago
The half-life of radium-224 is approximately 3.66 days. Step 1 of 3 : Determine a so that A(t)=A0at describes the amount of radi
Dafna11 [192]

Answer:

a = 0.827468

Explanation:

given,

half life of radium-224 = 3.66 days

now,

 A(t) = A_0 a^t

t is the time

A₀ is the amount at t = 0

at t = 0 ,    A(0) = 1

A(3.66) = 1/2

at t = 3.66

A(t) = A_0 a^t

\dfrac{1}{2}= 1. a^{3.66}

taking log both side

3.66 log (a) = log (0.5)

       log a = -0.0822

now,a = 10^{-0.0822}

         a = 0.827468

4 0
3 years ago
A proton, traveling with a velocity of 1.6 × 106 m/s due east, experiences a maximum magnetic force of 8.0 × 10-14 N. The direct
uranmaximum [27]

Answer:

The magnitude of magnetic field is 0.312 T and direction of the magnetic field is out of the page.

Explanation:

Given:

Velocity of proton v = 1.6 \times 10^{6} \frac{m}{s}

Magnetic force F = 8 \times 10^{-14} N

Charge of proton q = 1.6 \times 10^{-19}C

The magnetic force experience by proton in magnetic field is given by,

    F =qvB \sin \theta

Here magnetic force experienced by proton is maximum so we take \sin \theta = 1

    F = qvB

    B = \frac{F}{qv}

    B = \frac{8 \times 10^{-14} }{1.6 \times 10^{-19} \times 1.6 \times 10^{6}  }

    B = 0.312 T

According to the left hand rule the direction of magnetic field is out of the page.

Therefore, the magnitude of magnetic field is 0.312 T and direction of the magnetic field is out of the page.

7 0
3 years ago
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