Answer:
The stitches and dimples around a baseball and a golf ball respectively, disturbs the air drag on the balls once they are in motion, allowing the them to travel more easily.
Explanation:
The stitches on a baseball disturbs the air drag on the ball when the ball is in motion, allowing the ball to travel more easily. Depending on the orientation of the ball in flight, the drag changes as the flow is disturbed by the stitches.
A smooth ball with no stitches or dimples has more air drag that opposes the motion.
A golf ball is smooth ball with dimples to create a thin turbulent boundary layer of air that clings to the ball's surface. This allows the smoothly flowing air to follow the ball's surface a little farther around the back side of the ball, thereby decreasing the size of the wake, and allowing the ball to travel more easily.
Answer:
<h2>151.8 N</h2>
Explanation:
The force acting on the blimp can be found by using the formula
<h3>f = p × a</h3>
p is the pressure
a is the area
3000 cm² = 0.3 m²
From the question we have
f = 506 × 0.3
We have the final answer as
<h3>151.8 N</h3>
Hope this helps you
That’s the color of the ball?
Answer: I have no idea either i need help aswell
Explanation:
Answer:
At time 10.28 s after A is fired bullet B passes A.
Passing of B occurs at 4108.31 height.
Explanation:
Let h be the height at which this occurs and t be the time after second bullet fires.
Distance traveled by first bullet can be calculated using equation of motion
![s=ut+0.5at^2 \\](https://tex.z-dn.net/?f=s%3Dut%2B0.5at%5E2%20%5C%5C%20)
Here s = h,u = 450m/s a = -g and t = t+3
Substituting
![h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9](https://tex.z-dn.net/?f=h%3D450%28t%2B3%29-0.5%5Ctimes%209.81%5Ctimes%20%28t%2B3%29%5E2%3D450t%2B1350-4.9t%5E2-29.4t-44.1%5C%5C%5C%5Ch%3D420.6t-4.9t%5E2%2B1305.9%20)
Distance traveled by second bullet
Here s = h,u = 600m/s a = -g and t = t
Substituting
![h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\](https://tex.z-dn.net/?f=h%3D600t-0.5%5Ctimes%209.81%5Ctimes%20t%5E2%3D600t-4.9t%5E2%5C%5C%5C%5Ch%3D600t-4.9t%5E2%20%5C%5C%20)
Solving both equations
![600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\](https://tex.z-dn.net/?f=600t-4.9t%5E2%3D420.6t-4.9t%5E2%2B1305.9%5C%5C%5C%5C179.4t%3D1305.9%5C%5C%5C%5Ct%3D7.28s%20%5C%5C%20)
So at time 10.28 s after A is fired bullet B passes A.
Height at t = 7.28 s
![h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\](https://tex.z-dn.net/?f=h%3D600%5Ctimes%207.28-4.9%5Ctimes%207.28%5E2%5C%5C%5C%5Ch%3D4108.31m%20%5C%5C%20)
Passing of B occurs at 4108.31 height.