If f(x)=x^2 +2x -1
a) 2=x^2+2x-1
0=x^2+2x-3
0=(x+3)(x-1) x=-3 or 1
b) 14=x^2+2x-1
0=x^2+2x-15
0=(x+5)(x-3) x=-5 or 3
c) 7=x^2+2x-1
0=x^2+2x-8
0=(x+4)(x-2) x=-4 or 2
d) -1=x^2+2x-1
0=x^2+2x+0
0=(x+2)x x=0 or -2
Since this function involves a quadratic equation, there are technically two possible inputs that will give you the same output. In your case, you just have to match one of the possible inputs to its output (the numbers on the left originally given, from what it seems.) Hope this helps
Answer:
10) is the last one
11)the first one
:)
Step-by-step explanation:
6-5 = 1, 1 + 3 = 4
Answer is 4
We have that
1/16 = 64<span>^x
applying log both sides
log(1/16)=log(</span>64^x)
log 1-log16=x*log64
-log 16=x*log 64
divide by log 64 both sides
x=-log 16/log 64
log 16=log 2^4-----> 4*log 2
log 64=log 2^6-----> 6*log 2
-log 16/log 64=(-4*log 2)/(6*log 2)-----> -4/6------> -2/3
the answer is
x=-2/3
Answer:
B.
Step-by-step explanation:
First you need to figure out how many numbers there are, so with this you can simply count 10. Then use the formula to plug in the numbers: 10(22-77)/2 to get the answer.
