Answer:
![- \frac{8}{\pi}](https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B8%7D%7B%5Cpi%7D%20)
Step-by-step explanation:
Use slope formula.
Rise over run.
Or
y over x.
![\frac{ {y}^{2} - y {}^{1} }{ {x}^{2} - x {}^{1} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7By%7D%5E%7B2%7D%20%20-%20y%20%7B%7D%5E%7B1%7D%20%7D%7B%20%7Bx%7D%5E%7B2%7D%20-%20x%20%7B%7D%5E%7B1%7D%20%20%7D%20)
Over changes in x value would be - 3/4 pi.
Plug in seepage intervals for x to find y.
![6 \cos(2(\pi) - 4](https://tex.z-dn.net/?f=6%20%5Ccos%282%28%5Cpi%29%20%20-%204)
In the regular function,
![\cos(\pi) = 1](https://tex.z-dn.net/?f=%20%5Ccos%28%5Cpi%29%20%20%3D%201)
Since our period is 2, it would stay the same since 1x2=2
Since our amplitude is 6, our y value now is 6.
Since our vertical shift is -4, our y value is 2.
So
![6 \cos(2(\pi)) - 4 = 2](https://tex.z-dn.net/?f=6%20%5Ccos%282%28%5Cpi%29%29%20%20-%204%20%3D%202)
![{x}^{2} = \pi \: \: \: \: {y}^{2} = 2](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20%5Cpi%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%7By%7D%5E%7B2%7D%20%20%3D%202)
Let do the other point,
![\cos( \frac{\pi}{4} ) = \frac{ \sqrt{2} }{2}](https://tex.z-dn.net/?f=%20%5Ccos%28%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%29%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B2%7D%20%7D%7B2%7D%20)
Our period is 2 so
![\frac{ {\pi} }{4} \times \frac{2}{1} = \frac{\pi}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B%5Cpi%7D%20%7D%7B4%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B1%7D%20%20%3D%20%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20)
![\cos( \frac{\pi}{2} ) = 0](https://tex.z-dn.net/?f=%20%5Ccos%28%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%29%20%20%3D%200)
Multiply this by 6.
It stays 0 then subtract 4 we get
![6 \cos(2( \frac{\pi}{4} )) - 4 = - 4](https://tex.z-dn.net/?f=6%20%5Ccos%282%28%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%29%29%20%20-%204%20%3D%20%20-%204)
Use the earlier formula, slope
![\frac{2 + 4}{ - \frac{3\pi}{4} } = - \frac{8}{\pi}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20%20%2B%204%7D%7B%20-%20%20%5Cfrac%7B3%5Cpi%7D%7B4%7D%20%7D%20%20%3D%20%20-%20%20%5Cfrac%7B8%7D%7B%5Cpi%7D%20)
2
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
r is the equation for a circumference.
2(3.141592)(12.6/2)
your answer is 39.58inches
Answer:
26.
Step-by-step explanation:
The first partner in the handshake can be any one of 15 people.
The second partner can be any one of 14 people.
So the total number of possible arrangements is (15 x 14) = <u>210</u> .
<em><u>BUT . . . .</u></em>
If Mr. Smith and Mr. Jones are shaking hands, it doesn't matter which one is the first partner and which one is the second partner ... It's the same handshake either way.
That number of ' <u>210</u> ' up above counted both ways separately. The real number of handshakes <em>between different people</em> is half of that 210/2 = <em>105 handshakes</em>.