The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm. What is the approx
imate difference between m∠C and m∠A?
2 answers:
Check the picture below.
make sure your calculator is in Degree mode, if you need the angles in degrees, or Radian mode if you need them in radians.
and their difference is clearly just C - A.
make sure your calculator is in Degree mode, if you need the angles in degrees, or Radian mode if you need them in radians.
and their difference is clearly just C - A.
Answer
Difference between m∠C and m∠A= 44.76
Step-by-step explanation:
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.
Hypotenuse AC = 13 cm
So angle B is right angle = 90 degrees
AC is the hypotenuse
BC is the adjacent side for C
cos (c)= adjacent side / hypotenuse
C= cos^-1(BC/AC)
angle B is a right angle= 90 degree
Angle C= 67.38 degrees
Sum of angles in a triangle is 180°
A + B +C = 180
A + 90 + 67.38 = 180
A= 180 - 90 - 67.38=22.62
Difference between m∠C and m∠A= 67.38 - 22.62=44.76
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Answer:
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Step-by-step explanation:
We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 85 - 1 = 84
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.989.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
92% confidence interval:
Following the sample logic, the critical value is 1.772. So
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).