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8090 [49]
3 years ago
12

A postage stamp is shaped like a rectangle with a perimeter of 88 millimeters. The length (x) is 10 millimeters less than twice

the width (y). The system of equations shown below represents this situation.
x = 2y - 10
2x + 2y = 88

Which statement is true?

Question 4 options:

The width of the stamp is 1 millimeters


The length of the stamp is 36 millimeters


The width of the stamp is 8 millimeters less than the length.


The length of the stamp is 10 millimeters greater than the width
Mathematics
1 answer:
RoseWind [281]3 years ago
7 0
Length = x, width = y

x = 2y - 10....so sub in 2y - 10 for y back in the other equation

2x + 2y = 88
2(2y - 10) + 2y = 88
4y - 20 + 2y = 88
4y + 2y = 88 + 20
6y = 108
y = 108/6
y = 18

x = 2y - 10
x = 2(18) - 10
x = 36 - 10
x = 26

so the length (x) is 26 mm and the width (y) is 18 mm

The width of the stamp is 8 mm less then the length (26 - 18 = 8)


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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

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We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

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