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8090 [49]
3 years ago
12

A postage stamp is shaped like a rectangle with a perimeter of 88 millimeters. The length (x) is 10 millimeters less than twice

the width (y). The system of equations shown below represents this situation.
x = 2y - 10
2x + 2y = 88

Which statement is true?

Question 4 options:

The width of the stamp is 1 millimeters


The length of the stamp is 36 millimeters


The width of the stamp is 8 millimeters less than the length.


The length of the stamp is 10 millimeters greater than the width
Mathematics
1 answer:
RoseWind [281]3 years ago
7 0
Length = x, width = y

x = 2y - 10....so sub in 2y - 10 for y back in the other equation

2x + 2y = 88
2(2y - 10) + 2y = 88
4y - 20 + 2y = 88
4y + 2y = 88 + 20
6y = 108
y = 108/6
y = 18

x = 2y - 10
x = 2(18) - 10
x = 36 - 10
x = 26

so the length (x) is 26 mm and the width (y) is 18 mm

The width of the stamp is 8 mm less then the length (26 - 18 = 8)


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if I || m then 5x+12 =m<2 and m<2 + 2x + 14 = 180°

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​
jeka57 [31]
Choice c us the correct answer
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Carlos is correct

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Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.

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vekshin1

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160 units and $6400

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We have that the cost per x unit is: 20 * x + 0.25 * x ^ 2

the price per unit is 100, therefore revenue for each unit would be 100 * x

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for the maximum value profit we must derive and equal 0:

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