Question

Solve the following quadratic equation for all value of c i'm simplest form 5(x-2)^2=20

Answer 1

Answer:

x=-2 and x=0

Step-by-step explanation:

5(x-2)^2 =  20; divide by 5 both sides

(x-2)^2 = 4; take the square root of both sides

(x-2) = ±2, now set it equal to positive 2 and negative 2

x-2 = 2

x=4

AND

x-2 = -2

x=0

Answer 2

Answer:

The values of x is 0 and 4.

Step-by-step explanation:

You have to divide 5 by both sides;

$5 {(x - 2)}^{2} = 20$

${(x - 2)}^{2} = 4$

You have to expand the brackets;

${x}^{2} - 4x +4 = 4$

${x}^{2} - 4 x = 0$

You have to factorize;

$x(x - 4) = 0$

Lastly, you have to solve it;

$x = 0$

$x = 4$