Answer:
y=x+2 will be a positive upwards graph that has a slope of 1 this means it will cross diagonally perfectly it won't change directions and it won't go up more than down or left more than right. It will cross the x axis at 2.
y=-x+2 It will be the same thing but this time starts from the top left and goes down gets to x axis at positive 2 again
y=|x|+2 This will go down from top left again and hit positive 2 on y axis then go back up making a v it does not curve and it does have a perfect slope of 1 making it easy to graph.
Step-by-step explanation:
Answer:
x-int=-8, y-int=2,-4
Step-by-step explanation:
for the x-int
you set x to 0 then solve the equation to get -8
for the y-int
you set y(or in this case f(x)) to 0 then solve. You solve this by spilting this into 2 linear equations; x-2=0 and x+4=0, then you solve them both to get the two y-intercepts, 2 and -4
Formula for distance between two points:
d = √((x₂-x₁)² + (y₂-y₁)²)
Let point 1 be (-3, 11) and point 2 be (5, 5)
Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.
d = √((x₂-x₁)² + (y₂-y₁)²)
= √((5- -3)² + (5-11)²)
= √((5+3)² + (5-11)²)
= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36
= √(64 + 36)
= √(100)
= 10
Distance = 10 units.
The absolute value - or distance from zero, is fairly simple to find. Make your final answer positive to find it.
