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astra-53 [7]
3 years ago
5

Solve the following quadratic equation for all value of c i'm simplest form 5(x-2)^2=20

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

x=-2 and x=0

Step-by-step explanation:

5(x-2)^2 =  20; divide by 5 both sides

(x-2)^2 = 4; take the square root of both sides

(x-2) = ±2, now set it equal to positive 2 and negative 2

x-2 = 2

x=4

AND

x-2 = -2

x=0

atroni [7]3 years ago
6 0

Answer:

The values of x is 0 and 4.

Step-by-step explanation:

You have to divide 5 by both sides;

5 {(x - 2)}^{2}  = 20

{(x - 2)}^{2}  = 4

You have to expand the brackets;

{x}^{2}  - 4x +4 = 4

{x}^{2}  - 4 x = 0

You have to factorize;

x(x - 4) = 0

Lastly, you have to solve it;

x = 0

x = 4

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