<span><span>
q−9</span>=12
</span>Step 1: Add 9 to both sides.
<span><span><span>q−9</span>+9</span>=<span>12+9
</span></span><span>q=21
</span>Answer:
<span>q=21</span>
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
Answer: If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.
Step-by-step explanation:
Let x = Number of weeks.
As per given question ,
Weight of Frank after x weeks = 160+2x (pounds)
Weight of John after x weeks = 208-3x (pounds)
When Weight of Frank= Weight of John



Weight of Frank after 9.6 weeks = 160+2(9.6) = 179.2 pounds
Weight of John after 9.6 weeks = 208-3(9.6)=179.2 pounds
Hence, If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.
Answer:
6 pounds
Step-by-step explanation:
3/8×8/1=24/8=3
6/1×1/2=6/2=3
3+3=6
This answer would be a cuboid because it has parallel,perpendicular,and diagonal cross sections