Please help!!!

Jane is organizing a fundraiser to buy a ping-pong table for the community center. The table costs $500.00. Jane is asking contr

kogti [31]

Answer:

Function: C = 500 / n

Jane must recruit 20 more contributors or 25 contributors in total for the cost of each share to be $20.

Step-by-step explanation:

1. Cost per share, C, with respect to the number of contributors, n is

C = 500 / n

So, with 5 contributors, the price is $100 per share. $100 = 500/5

2. C= $20

20= 500 / n

20 * n = 500 * n

20n = 500

n= 25

She already has 5 contributors, so she needs 20 more.

4 0

4 years ago

A company making backpacks charges $29.99 for each backpack. It costs $6.45 to make each backpack. The company can make backpack

Ne4ueva [31]

A minimum of 220 backpacks must be produced to obtain the desired benefits.

Since a company making backpacks charges $ 29.99 for each backpack, and it costs $ 6.45 to make each backpack, and the company can make backpacks in multiples of 10 and there is $ 1,000 in fixed costs, and the company wants to make at least $ 4,000 profit each week, to determine how many backpacks should be produced, the following calculation must be performed:

29.99 - 6.45 = 23.54
500 x 23.54 - 1000 = 10,770
250 x 23.54 - 1000 = 4.885
220 x 23.54 - 1000 = 4,178.80
210 x 23.54 - 1000 = 3,943.40

Therefore, a minimum of 220 backpacks must be produced to obtain the desired benefits.

Learn more in brainly.com/question/15713474

8 0

3 years ago

Read 2 more answers

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$