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galina1969 [7]
2 years ago
14

Can someone help for my math test? its 20 points and ill be giving brainiest!

Mathematics
2 answers:
Ludmilka [50]2 years ago
8 0

Answer: 20

Part 1:

You want to make a rectangular dog pen using 20 yards of fencing.  The side lengths must be in whole yards.  Create as many different rectangular pens as you can.

Part 2:

Which dog pen gives your dog the most space to run around and play in?  Write a sentence explaining how you know.

Part 3:

You want to build the rectangular dog pen with 20 yards of fencing against your house which is 20 yards wide.  Which dimensions will give you the most space for your dog?

Part 4:

One of your friends just got a puppy.  She is going to buy fencing with her parents this weekend to build her own pen.  Explain to her how to design the fence so that her puppy will have the biggest pen possible, as well as how you know it will be the biggest pen possible.

weqwewe [10]2 years ago
4 0

Answer:

the length in fraction form would be 16 1/2 rounded to the nearest 10 would be 20

Step-by-step explanation:

because 16.5=16 1/2

16.5=17

17=20

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Answer:

Therefore, the sampling distribution of \bar{x} is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The 95% interval estimate of the population mean \mu is

LCL = 7.431 hours to UCL = 10.569 hours

Step-by-step explanation:

Let X be the number of hours a legal professional works on a typical workday. Imagine that X is normally distributed with a known standard deviation of 12.6.

The population standard deviation is  

\sigma = 12.6 \: hours

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

The sample size is

n = 250

The sample mean is  

\bar{x} = 9 \: hours  

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The population mean would be the same as the sample mean that is

 \mu = \bar{x} = 9 \: hours

The sample standard deviation would be  

$ s = {\frac{\sigma}{\sqrt{n} }  $

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$ s = {\frac{12.6}{\sqrt{250} }  $

s = 0.7969 \: hours

Therefore, the sampling distribution of \bar{x} is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The population mean confidence interval is given by

\text {confidence interval} = \mu \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sampling size, s is the sample standard deviation and  is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 250 - 1 = 249

From the t-table at α = 0.025 and DoF = 249

t-score = 1.9695

MoE = t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\\\MoE = 1.9695\cdot \frac{12.6}{\sqrt{250} } \\\\MoE = 1.9695\cdot 0.7969\\\\MoE = 1.569\\\\

So the required 95% confidence interval is

\text {confidence interval} = \mu \pm MoE\\\\\text {confidence interval} = 9 \pm 1.569\\\\\text {LCI } = 9 - 1.569 = 7.431\\\\\text {UCI } = 9 + 1.569 = 10.569

The 95% interval estimate of the population mean \mu is

LCL = 7.431 hours to UCL = 10.569 hours

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3 years ago
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