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3 years ago

Help me please ❤️❤️❤️❤️

Mathematics

1 answer:

melomori [17]3 years ago

4 0

In a quadratic function, $f(x)= ax^2+bx+c$ the leading coefficient is $a$ , i.e. the coefficient of $x^2$ , and the constant term is $c$ , i.e. the coefficient without any power of $x$ .

So, if you want leading coefficient 2 and constant term -3, your function needs to be like

$f(x)=2x^2+bx-3$

for any value of $b$ . Among your options:

The first is not a quadratic (it starts with $x^3$ )
The second has leading term -3 and constant term 2
The third is not a quadratic (same as the first)
The last is correct.

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What is 1 5/6 + 1/2 ? a. 14/6 b. 17/12 c. 17/6 d. 25/12

Vladimir79 [104]

Make bottom numbers same

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1 and 5/6=1+5/6=6/6+5/6=11/6

1/2 and 11/6
2 times 3=6
1/2 times 3/3=3/6

1/2+11/6=3/6+11/6=(4+11)/6=14/6

answer is A

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4 years ago

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3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago

How do i solve a triangles area

shusha [124]

Answer:

Area = 1/2 Base x height

Step-by-step explanation:

To find the area of a triangle, multiply the base of the height and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into two triangles.

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4 years ago