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Oxana [17]
3 years ago
12

We bought 3 3/4 pound bags of bird seed. A. What is the total weight of the birdseed they bought? B. If each smaller bag contain

s 1 1/2 pounds, how many bags can they make? C. Will there be any birdseed
Left over? .
Mathematics
2 answers:
Zanzabum3 years ago
7 0
3 * 3/4 = 9/4 = 2 1/4 lbs <== total weight

(9/4) / (1 1/2) =
(9/4) / (3/2) =
9/4 * 2/3 =
18/12 = 3/2 = 1 1/2.....they can flll 1 1/2 bags.....or they can fill 1 bag leaving 
9/4 - 3/2 = 9/4 - 6/4 = 3/4 lbs left
Solnce55 [7]3 years ago
5 0

The <em><u>correct answers</u></em> are:

A)  2 1/4 pounds; B) 1 full bag; C) yes, 3/4 of a pound.

Explanation:

Purchasing three 3/4 pound bags gives us 3(3/4) = (3/1)(3/4) = 9/4 = 2 1/4 pounds of bird seed.

Since each small bag would hold 1 1/2 pounds, we divide to find the number of bags we can make:

2 1/4 ÷ 1 1/2 = 9/4 ÷ 3/2 = 9/4 × 2/3 = 18/12 = 1 6/12 = 1 1/2

This means we can make 1 bag and have enough for half of another bag.  Half of a 1 1/2 pound bag is:

1/2(1 1/2) = 1/2(3/2) = 3/4 of a pound.

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Palawbhehrht awnser yes or mo
wariber [46]

Answer:

yes

Step-by-step explanation:

4 0
2 years ago
at a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. Th
VladimirAG [237]

Answer:

The number of tickets sold to the public was 375

Step-by-step explanation:

<u><em>The complete question is</em></u>

At a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. The students paid $15 and public $25. When all the tickets were sold, $10,500 was collected. How many tickets were sold to the public?

Let

x ----> number of tickets sold to the students

y ----> number of tickets sold to the public

we know that

x+y=450 ----> equation A

15x+25y=10,500 ----> equation B

Solve the system by graphing

The solution is the intersection point both graphs

using a graphing tool

The solution is the point (75,375)

see the attached figure

therefore

The number of tickets sold to the public was 375

6 0
4 years ago
Please answer the question above and pick an answer from the 3 provided
shutvik [7]

Answer:

B.

w=P-2l/2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Cblue%7B%5Cmathscr%7BHello%5C%3ABrainliacs%7D%7D%7D" id="TexFormula1" title="\box
andrew-mc [135]

For the reaction,

CO(g) + H_2 O(g) = CO_2(g) + H_2(g)

Initial concentration:

<u>0.1M</u> , <u>0.1M</u> , <u>0</u> , <u>0</u>

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

<u>(0.1 – x)M</u> , <u>(0.1 – x)M</u> , <u>xM</u> , <u>xM</u>

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

K_c = \frac{x²}{(0.1 – x)²} = 4.24

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

<em>a = 3.24, b = -0.848, c = 0.0424</em>

(for quadratic equation ax² + bx+c=0)

x =  \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}

=  > x =  \frac{ - ( - 0.848 \: ± \:  \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}

=  > x =  \frac{ - 0.848±0.4118}{6.48}

x_1 =  \frac{0.848 - 0.4118}{6.48} = 0.067

x_2 =  \frac{0.848 + 0.4118}{6.48} = 0.194

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

[CO_2] [H_2] = x = 0.067M

[CO] [H_2 O] = 0.1 - 0.067 = 0.033M

7 0
3 years ago
It's due in 30 minutes!!
Doss [256]
1st is 40/100 = 4/10 =40%
2nd is 52/100 =26/50 = 52%
3rd is 24/100 = 6/25 = 24%
4th is 9/100 = 9/100 = 9%
4 0
3 years ago
Read 2 more answers
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