P(t) = 40(2)^(kt)
<span>when t=10, (1990), N = 55 </span>
<span>55 = 40(2)^(10k) </span>
<span>1.25 = 2^(10k) </span>
<span>take the ln of both sides, hope you remember your log rules </span>
<span>10k = ln 1.25/ln 2 </span>
<span>10k = .32193 </span>
<span>k = .032193 </span>
<span>so P(t) = 40(2)^(.032193t) </span>
<span>in 2000, t = 20 </span>
<span>P(20) = 40(2)^(.032193(20)) </span>
<span>= 62.5 million </span>
<span>for the formula </span>
<span>P(t) = a(2)^(t/d), d = the doubling time </span>
<span>so changing .032193t to t/d </span>
<span>= .032193t </span>
<span>= t/31.06 </span>
<span>so the doubling time is 31.06 </span>
<span>another way would be to set </span>
<span>80 = 40(2)^(.032193t) </span>
<span>2 = (2)^(.032193t) </span>
<span>.032193t = ln 2/ln 2 = 1 </span>
<span>t = 31.06</span>
The hundredths is the second place to the right, and following the rule of rounding, the number behind the 4 which is the hundredths place is greater than 5 which makes the 4 become a 5 so the answer is 12.15
Answer:
B
Step-by-step explanation:
A triple a, b, c is a Pythagorean triple if
Check all options:
A.
B.
C.
D.
1- 6
2- 4
3- 2
And that’s all I can tell you? It’s decreasing so I don’t think 10 would have any stars unless if negative numbers are allowed