A high polled students for their favorite subject in school the 3125 students participated in the survey

Mathematics

1 answer:

Furkat [3]3 years ago

6 0

What is the rest of the question

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What is the probability of selecting a red card from a standard deck of 52 playing cardships that does not contain a joker?

Rasek [7]

We know that the deck of cards contain half red and half black cards or you can say we have 26 red cards and 26 black cards.
we have to find probability of red cards from a deck of cards
so,
probability (selecting red card) = $\frac{26}{52}$
= $\frac{1}{2}$

Probability ( selecting red card ) = <span> $\frac{1}{2}$ Answer</span>

4 0

3 years ago

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Which don’t lie??????????!!!!!

garri49 [273]

Answer:

I think its -12. If you apply y2-y1/ x2-x1 to the equation.

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4 years ago

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Can someone please help <3

Nimfa-mama [501]

Answer:

number (c)

Step-by-step explanation:

I am not sure about this

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3 years ago

The answer for this question

Savatey [412]

I hope this helps you

8 0

3 years ago

If ex + e⁻¹= 2, then x =..

harkovskaia [24]

Answer:

$\rm x = \dfrac{2e - 1}{ {e}^{2} }$

Step-by-step explanation:

$\rm Solve \: for \: x: \\ \rm \longrightarrow ex + {e}^{ - 1} = 2 \\ \\ \rm \longrightarrow e x + \dfrac{1}{e} = 2 \\ \\ \rm Subtract \: \dfrac{1}{e} \: from \: both \: sides: \\ \rm \longrightarrow e x + \dfrac{1}{e} - \dfrac{1}{e} = 2 - \dfrac{1}{e} \\ \\ \rm \longrightarrow ex = \dfrac{2e}{e} - \dfrac{1}{e} \\ \\ \rm \longrightarrow ex = \dfrac{2e - 1}{e} \\ \\ \rm Divide \: both \: sides \: by \: e: \\ \rm \longrightarrow \dfrac{ex}{e} = \dfrac{2e - 1}{e \times e} \\ \\ \rm \longrightarrow x = \dfrac{2e - 1}{ {e}^{2} }$

6 0

3 years ago