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Jobisdone [24]
2 years ago
5

How to find a least common demoniator

Mathematics
1 answer:
katrin [286]2 years ago
3 0
To find the LCD first convert all integers and mixed numbers (mixed fractions) into fractions. Then find the least common multiple ( LCM ) of the denominators which is equal to the least common denominator ( LCD ). You can then rewrite each term as an equivalent fraction with the LCD .
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Nine raised to the five-minus-two power?
bonufazy [111]

Answer:

1. 9 raised to the third power is 729

2. 4 raised the the power of 1 is 1

Step-by-step explanation:

9*9= 81*9=729

4*1=4

8 0
3 years ago
What is the volume of the cone?<br> Cone v = BA<br> 10 cm<br> 0<br> 0<br> 7 cm<br> 0<br> 0
Drupady [299]
If you could Explain more
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2 years ago
What integers are plotted on the number line below?
qaws [65]

Answer:

The answer is c. hope this helps

Step-by-step explanation:

8 0
2 years ago
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If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
The distance between -18 and 15 is equal to_______
ArbitrLikvidat [17]

Answer:

sorry I forgot try googling it

3 0
3 years ago
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