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BabaBlast [244]
3 years ago
10

You want to purchase a ticket to the movies. A ticket costs at least $12. You have $3. How much more money do you need to purcha

se a ticket? Write and solve an inequality.​
Mathematics
2 answers:
BaLLatris [955]3 years ago
6 0

Answer:

I think the answer is$12 - $3 = $9

the amount u need is $9 to have the complete amount u need to purchase the ticket

Paladinen [302]3 years ago
3 0

Answer:

Step-by-step explanation:

We have $3, we need more money $x, so that the sum will be $12 or more

                3                      +                    x                                        ≥12

the inequality is 3+x ≥ 12

solve for x

3+x ≥ 12, subtract 3 from both sides of the equation

3-3+x ≥1 2-3

x ≥ 9, we need $9 or more to purchase a ticket

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Obtain the derivative of y=2x^2​
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Answer: 4x

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Heya user☺☺

Option c is correct

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6 0
3 years ago
Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \  \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

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5 0
3 years ago
9. Which of these was an example of US industrial mobilization for war? (5.1.B) A. Increased factory production of tanks and pla
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5 0
3 years ago
0.9 of Karen's Science score is equal to 0.75 of her Math score and 0.8 of her Chemistry score. Given that Karen scored 96 marks
DochEvi [55]

You have to formulate equations for this problem.

Let S = Science score

      M = Math score

       C = Chemistry score

To illustrate the given:

0.9S = 0.75M

0.9S = 0.8C

You are given that Karen’s Math score is 96 marks. You have to substitute the Math score to the first equation.

0.9S = 0.75(96)

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Therefore, Karen’s Science score is 80. Now, you have to substitute the Science score to the second equation.

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So, Karen’s Chemistry score is 90.

Therefore, the total score of the 3 subjects is 266 (96 + 80 + 90).

5 0
3 years ago
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