Let: v = Olga's speed t = the time Anna spent going to school (3 km/hour) t/2 = the time Anna spent running back home with speed of 6 km/hour So, t + t/2 = 3t/2 is the total time In the meantime distance = speed*time and the both made the same distance we can put it as: 3t + 6*(t/2) = (3t/2)*v 6t = (3/2)tv divide both sides by t (3/2)v = 6 v = 2*6/3 v = 4 km/hour Olga's speed was 4 km/hour.
Step by Step Solution. Least Common Multiple is : 120. Calculate Least Common Multiple for : 3, 8 and 10. Factorize of the above numbers : 3 = 3. 8 = 23 10 = 2 • 5. Build a prime factors table. ...