25y.......140x
36y..........x
Cross multiply
25x= 36*140
25x= 5040
x= 5040/25
x= 1008/5
x= 201.6
When y=36 the x will = 201.6
I hope that's help !
No hope this helps bc it’s being multiplied and even then u simplify
Answer: In number 1 the answer is 2. Number 2 the answer is 7. Number 3 you read the problem as 4 x 4 x 4 or 4 to the 3rd. For number 4 it's 2x2x2x2x2x2x2 or 2 to the 7th power. Number 5 is right. For number 6 B. is 5. C is 6
Hope this helps
Step-by-step explanation:
Answer:
- y = 81-x
- the domain of P(x) is [0, 81]
- P is maximized at (x, y) = (54, 27)
Step-by-step explanation:
<u>Given</u>
- x plus y equals 81
- x and y are non-negative
<u>Find</u>
- P equals x squared y is maximized
<u>Solution</u>
a. Solve x plus y equals 81 for y.
y equals 81 minus x
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b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.
P equals x squared left parenthesis 81 minus x right parenthesis
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c. Find the domain of the function P found in part b.
left bracket 0 comma 81 right bracket
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d. Find dP/dx. Solve the equation dP/dx = 0.
P = 81x² -x³
dP/dx = 162x -3x² = 3x(54 -x) = 0
The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...
P is maximized at (x, y) = (54, 27).