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natita [175]
4 years ago
14

Find the coordinates of the midpoint of the segment whose endpoints are H(8, 13) and K(10, 9).​

Mathematics
1 answer:
Anuta_ua [19.1K]4 years ago
6 0

Good evening

Answer:

<h2>M(9 , 11)</h2>

Step-by-step explanation:

let Point M(x , y) be the midpoint of segment HK then

x = (8+10)/2 = 18/2 = 9

y = (13+9)/2 = 22/2 = 11.

:)

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I need help plz plz plz plz
dem82 [27]

9514 1404 393

Answer:

   (a)  34 ft²

Step-by-step explanation:

The "top" and "back" together have a height of 2 ft + 1 1/2 ft = 3 1/2 ft. The bottom and front will have the same height, so the central vertical rectangle in the net will have a height of 2×(3 1/2 ft) = 7 ft. It is shown as having a width of 4 ft, so its area is ...

  A = WH = (4 ft)(7 ft) = 28 ft²

__

The two areas labeled "left" and "right" are shown as having a height of 1 1/2 ft. Their width is the same as the width of the bottom (or top), so is 2 ft. The total area of the left and right sides is then ...

  left + right = 2WH = 2(2 ft)(1 1/2 ft) = 6 ft²

That makes the area of the entire net be ...

  total surface area = 28 ft² +6 ft² = 34 ft²

The surface area of the box is 34 square feet.

4 0
3 years ago
2x+5y=-55 y=3x+6 What is the solution
Arlecino [84]
Let: eq 1:2x+5y=-55
eq 2:y=3x+6
by substituting eq 2 in eq 1 we get,
2x+5(3x+6)=-55
2x+15x+30+55=0
17x + 85=0
x=-85/17
x=-5
By substituting x value in eq 2,
we have,
y=3(-5)+6=-15+6=-9
3 0
3 years ago
Read 2 more answers
suppose we want to choose 5 letters, without replacement, from 13 distinct letters. (a) how many ways can this be done, if the o
CaHeK987 [17]

A. The number of possible ways can this be done, if the order of the choices is not taken into consideration is 1, 287 ways

B. The number of possible ways can this be done, if the order of the choices is taken into consideration is 154,440 ways

<h3>What is meant by permutation and combination?</h3>

Combination and permutation are two alternative strategies in mathematics to divide up a collection of components into subsets. The subset's components can be listed in any order when combined. The components of the subset are listed in a permutation in a certain order.

A. We want to select 5 objects from a total 13, without considering the order in which they are chosen.

The correct way to do this exists by utilizing the combination formula since order exists not considered;

Therefore, we have ; 13 C 5 read as 13 combination 5;

Let the equation of combination be n C r = n!/(n-r)!r!

substituting the values in the above equation, we get

13!/(13-8)!8! = 13!/5!8! = 1,287 ways

B. By considering order, we shall be using the permutation formula;

Let the equation of permutation be n P r = n!/(n-r)!

substituting the values in the above equation, we get

13 P 5 = 13!/(13-5)!

= 13!/(13-5)! = 13!/8! = 154,440 ways

To learn more about permutation and combination refer to:

brainly.com/question/11732255

#SPJ4

3 0
1 year ago
What's the domain for this???
nikklg [1K]
All Real Numbers is the domain
8 0
3 years ago
Read 2 more answers
Make up this problem yourself 3 divided by 1/2
Helen [10]

Answer:

3 : (1/2) =\frac{6}{1} =6

Step-by-step explanation:

Divide: 3 : \frac{1}{2} =\frac{3}{1} *\frac{2}{1} =\frac{3 * 2}{1*1} =\frac{6}{1} =6

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of \frac{1}{2} is \frac{2}{1}) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.

In words - three divided by one half = six.

8 0
3 years ago
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