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3 years ago

2x+5y=-55 y=3x+6 What is the solution

Mathematics

2 answers:

zloy xaker [14]3 years ago

6 0

Hey there!!

We have 2 equations.

... 2x+5y=-55 and y=3x+6

Substitution method:

... 2x+5(3x+6)=-55

... 2x+15x+30=-55

... 17x+30=-55

Subtracting 30 on both sides:

... 17x=-55-30

... 17x=-85

Dividing by 17 on both sides:

... x=-85/17

... x = -5

The value of x is -5.

We have:

... 2x+5y=-55

... 2(-5)+5y=-55

... -10+5y=-55

Adding by 10 on both sides:

... 5y=-55+10

... 5y=-45

Dividing by 5 on both sides:

... y=-9

Hence, the value of 'x' is -5 and the value of 'y' is -9.

Hope my answer helps!

Arlecino [84]3 years ago

3 0

Let: eq 1:2x+5y=-55
eq 2:y=3x+6
by substituting eq 2 in eq 1 we get,
2x+5(3x+6)=-55
2x+15x+30+55=0
17x + 85=0
x=-85/17
x=-5
By substituting x value in eq 2,
we have,
y=3(-5)+6=-15+6=-9

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3 years ago

Read 2 more answers

TOPIC: Forming and Solving Equations (An equation must be included as well please)

Tatiana [17]

1) let both have x ,
so putting in eqn ;

4x+0.50 = 9x-3
5x=2.50
x=0.50

therefore both have 50 p in the beginning !!

2) let the number be x

so in eqn;

(x+18)/2=5x
x+18=10x
9x=18
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so the number must be 2 !!

if you have still any problem, comment !!

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3 years ago

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A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

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Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

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3 years ago