it literally gave you the equation lol
y= 6x + 1/2
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
B. (100)(5)=500 C.(130)(5)=650 D.130/100= 650/500 E. There are 650 7th graders this year
Step-by-step explanation:
Just took it on Egde
The solutions would be 3 and 9
The answer is 75
First you subtract 180 and 165 to find that smallest angle inside the triangle(15). Then you add 15 and 90,the two angles you know, and do 180 - 105= 75.
The trick is that all angles inside a triangle equal 180 degrees. Hope this helps!
