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3 years ago

8

Find the perimeter of the figure.

1 answer:

lesantik [10]3 years ago

6 0

It would be 34 feet or 68 feet

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Rewrite the equations in slope-intercept form. Determine the slope.

notsponge [240]

This should have been worth more points, but anyways, here are the answers. Please give thanks :)

1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X
5.) Y = </span>X +6 <span>
6.) Y = 5 -3X
7.) Y = 2 +</span> $\frac{4}{3}$ <span>X
8.) </span>Y = $\frac{1}{2}$ X - 3<span>
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y = 1 - 5X
11.) Y = 2 - </span> $\frac{1}{3}$ <span>X
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span> $\frac{10}{3}$ <span> -2X
15.) Y = 2 +</span> $\frac{4}{3}$ <span>X
16.) Y = 2 +</span> $\frac{4}{3}$ <span>X
17.) Y = 1 - 5X
18.) Y = </span>[<span>tex] \frac{3}{4} [/tex]</span>X + 2

5 0

3 years ago

Thirty coins,all dimes and nickels,are worth $2.60. How many nickels are there?

quester [9]

Answer: 12 nickels

Step-by-step explanation:

4 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

3-4y=5x-6. The answer is (-5x^4-9)/4. Please explain how to get this.

xenn [34]

Answer:

The direction of mathematics teacher is study about the mathematics teacher is study about it is by step instructions

5 0

1 year ago

Tell whether it is possible to draw a figure with the given description.

sesenic [268]

Answer:

<h2>in my opinion it is not possible </h2>

Step-by-step explanation:

hope it helps you have a good day

3 0

2 years ago