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anyanavicka [17]
3 years ago
10

Hiiiooo!! Could someone please help me out with this❤️❤️❤️

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0

Answer: I am not completely sure, but I think it is 8.6

a_sh-v [17]3 years ago
5 0

Answer:

8

Step-by-step explanation:

3 divided by 4.8 = 0.625

5 divided by 0.625 = 8

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3/5=a+5/25 <br> A=<br> Using proportional reasoning
dusya [7]

Answer:

A = 2/5

Step-by-step explanation:

subtract 5/25 from both sides leaving A alone

3 0
3 years ago
Read 2 more answers
If c= the number of cars in a parking lot, which algebraic expression
sveticcg [70]

Answer:

D. C+9

Step-by-step explanation:

C represents the number of cars in the parking lot.

The number of cars increased by 9.

That means 9 plus the number of cars already available at the parking lot

That’s c + 9

4 0
4 years ago
RIGHT ANSWER GET BRAINLIEST
Alinara [238K]

a^n + a^n+1

rewrite a^n+1 as a^1 a^n

now you have a^n + a^1a^n

Factor out the common term to get the final answer:

a^n (1+a)

6 0
4 years ago
If one half of a number is 5 more than 6, what is the value when the number is tripled
blondinia [14]

Answer:

66

Step-by-step explanation:

let's use x to represent the unknown number

1/2x is 5 more than 6:

↓

1/2x=5+6

solve to find x

1/2x=11

x=22

next, it asks us what is the value of the number when the number is tripled

since we already found what x is equal to, we can multiply that by 3 to figure out its value when it's tripled

3(22)=66

3 0
3 years ago
PLEASE HELP! URGENT WILL GIVE BRAINLEST! PLEASE ANSWER ALL QUESTIONS!!! IF YOU DON'T I WILL REPORT.
Nesterboy [21]

Answer:

1.  b)  135°, 225°

2.  c)  0°, 180°

3.  a)  π/2

4.  b)  30°, 150°, 210°, 330°

5.  a)  1.25 radians and 4.39 radians

Step-by-step explanation:

<u>Question 1</u>

\begin{aligned}\cos \theta & = -\dfrac{\sqrt{2}}{2}\\\implies \theta & = \cos^{-1}\left(-\dfrac{\sqrt{2}}{2}\right)\\\\& = 135^{\circ} \pm 360^{\circ}n, 225^{\circ} \pm 360^{\circ}\\\\& = 135^{\circ}, 225^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}

<u>Question 2</u>

\begin{aligned}\cos^2 \theta-1 & = 0\\\implies \cos^2 \theta & = 1\\\cos \theta & = \pm1\\\theta & = \cos^{-1}(\pm1)\\& = 0^{\circ} \pm 360^{\circ}n, 180^{\circ} \pm360^{\circ}n\\& = 0^{\circ}, 180^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}

<u>Question 3</u>

\begin{aligned}\sin \theta & = 1\\\implies \theta & = \sin^{-1}(1)\\\theta & = \dfrac{\pi}{2}\pm2\pi n\\\theta & = \dfrac{\pi}{2}\quad \textsf{for}\:0 \leq \theta < 2 \pi \end{aligned}

<u>Question 4</u>

\begin{aligned}3 \tan^2 \theta-1 & = 0\\\implies \tan^2 \theta & = \dfrac{1}{3}\\\tan \theta & = \pm\dfrac{1}{\sqrt{3}}\\\theta & = \tan^{-1}\left(\pm\dfrac{1}{\sqrt{3}}\right)\\& = 30^{\circ}\pm180^{\circ}n, 150^{\circ}\pm180^{\circ}n\\& = 30^{\circ}, 150^{\circ}, 210^{\circ}, 330^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}

<u>Question 5</u>

\begin{aligned}2 \tan \theta -6 & = 0\\\implies \tan \theta & = 3\\\theta & = \tan^{-1}(3)\\\theta & = 1.25\pm \pi n\\\theta & = 1.25, 4.39 \quad \textsf{for}\:0^{\circ}\leq \theta < 2 \pi \end{aligned}

5 0
2 years ago
Read 2 more answers
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