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3 years ago

What are the coordinates of A? b) What are the coordinates of B?

Mathematics

1 answer:

a_sh-v [17]3 years ago

3 0

It’s 3,-5 and -4,-1 :))

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Riley has collected surveys for her final thesis project. One one question, 46.1% of respondents said that conditions were impro

ira [324]

Answer:

The maximum value of the confidence interval for this set of survey results is 51.73%.

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds depend on the sample proportion and on the margin of error.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this question:

Sample proportion: 46.1%

Margin of error: 5.63%.

Maximum value is the upper bound:

46.1+5.63 = 51.73

The maximum value of the confidence interval for this set of survey results is 51.73%.

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3 years ago

If one side of a square measures 6 units,<br> what is its area?

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Step-by-step explanation:

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2 years ago

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5. Over what interval is the following graph DECREASING? *

xxTIMURxx [149]

Answer:

(3, 13)

Step-by-step explanation:

The curve decreases from x = 3 to x = 13.

Answer: (3, 13)

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3 years ago

Joey had eight pencils in the morning. He gave some pencils away to friends who needed them. To determine the number of pencils

pshichka [43]

Answer : Subtract

Hope it help you

Please mark me brianliest

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1 year ago

Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y

Charra [1.4K]

I assume you mean $y_1=t^{-1}$ , and not $y_1=t-1$ , since this doesn't satisfy the ODE.

Assume a second solution of the form $y_2=vy_1$ , where $v$ is a function of $t$ . Then

${y_2}'=v'y_1+v{y_1}'$

${y_2}''=v''y_1+2v'{y_1}'+v{y_1}''$

Substituting into the ODE gives

$t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0$

$\implies tv''+v'=0$

$\implies(tv')'=0$

$\implies tv'=C$

$\implies v'=\dfrac Ct$

$\implies v=C_1\ln|t|+C_2$

$\implies y_2=\dfrac{\ln t}t$

where we omit the second term because it's already accounted for by $y_1$ .

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3 years ago

What are the coordinates of A? b) What are the coordinates of B?​

What are the coordinates of A? b) What are the coordinates of B?