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daser333 [38]
3 years ago
5

A video game system costs $185 and one video game costs $14.95. You can spend no more than $280 on the system and games. set up

and solve an inequality to calculate the maximum number of games you can purchase
Mathematics
1 answer:
disa [49]3 years ago
5 0

Answer:

Therefore the maximum number of video games that we can purchase  

is 6.

Step-by-step explanation:

i) Let us say the number of video game system we can buy that costs $185

 is x and the number of video games of cost $14.95 is y.

ii) The total amount we can spend on the purchase of the video game

   system is $280.

iii) Now with the amount of $280 mentioned in ii) we can see that the

   number  of game systems that can be bought is 1.

 Therefore x = 1.

 Therefore the equation we can write to equate the number of video

  games  and video game system is given by $185 + $14.95 × y ≤ 280

  Therefore 14.95 × y ≤ 280 - 185 = 95

  Therefore y ≤   95 ÷ 14.95 = 6.355

  Therefore the maximum number of video games that we can purchase  

   is 6.

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wlad13 [49]
1.

Parallelogram with base a = 20 in. and height h = 16 in.
Triangle with base a = 20 in. and height b = 8 in.

so:

A = A_P+A_T=a\cdot h+\frac{1}{2}\cdot a\cdot b=20\cdot16+\frac{1}{2}\cdot20\cdot8=320+80=\\\\=\boxed{400\text{ in}^2}

2.

Trapezoid with base b₁ = 14 cm, base b₂ = 4 cm and height h = 10 cm
Triangle with base b₁ = 14 cm and height x = 18 cm - 10 cm = 8 cm

so:

A=A_T+A_\Delta=\frac{1}{2}\cdot(b_1+b_2)\cdot h+\frac{1}{2}\cdot b_1\cdot x=\\\\=
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3.

We have three rectangles:

A=A_1+A_2+A_3=1\cdot 4+6\cdot5+18\cdot6=4+30+108=\boxed{142\text{ ft}^2}

4.

Area of a circle:

A_\circ=\pi\cdot r^2=3.14\cdot5^2=3.14\cdot25=78.5 \text{ cm}^2

Area of a rectangle:

A_R=8\cdot 6=48\text{ cm}^2

Area of the shaded region:

A=A_\circ-A_R=78.5-48=\boxed{30.5\text{ cm}^2}


3 0
3 years ago
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