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Lady bird [3.3K]
3 years ago
10

Jennifer chooses a playing card at random from a deck of 52 cards then she chooses another one. What is the probability that she

will get 2 cards that are hearts?
Mathematics
2 answers:
velikii [3]3 years ago
8 0
52 cards in a deck
4 suits
1/4 of 52 are hearts
1/4 of 52=13 cards

probability of getting 1 heart at first is 1/4

one card is taken out and assuming that it is the heart, 13-1=12,52-1=51
12/51

multiply
1/4 times 12/51=3/51=1/17

 
fredd [130]3 years ago
3 0
There is a \frac{13}{52} chance she will pick a heart the first time and a \frac{12}{51} that she will the second time.
The probability of this occurring thus is:
\frac{13}{52}* \frac{12}{51} =  \frac{13*2*2*3}{2*2*13*3*17}
=  \frac{1}{17}
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Afina-wow [57]
<span>Answer: 4

Explanation:

Translate the english language to mathematical (algebraic) language.

This implies to define the variables and translates the statements into equations.

1) Adventure Play sells an mp3 player for $18.00 and charges $3.25 per song.

Cost = price of the mp3 player + price each song * number of songs

Variables:

number of songs: n
price each son: $3.25
price of the mp3 player: $ 18.00
Cost: c(n), this means that the cost is a function of n.

c(n) = 18 + 3.25n

2) King Music sells a player for $23.00 and charges $2.00 per song. For how many songs will the cost be the same?

Using the same procedure used for Adventure Play case:

c(n) = 23 + 2n

3) Equal cost =>

18 + 3.25n = 23 + 2n

=> 3.25n - 2n = 23 - 18
=> 1.25n = 5
=> n = 5 / 1.25
=> n = 4

Answer: the cost will be the same for 4 songs.
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4 0
3 years ago
Identify a point of the line. y-1=3(x+6)<br> (Sorry there is no graph)
tia_tia [17]
Skip: -1/3 y-intercept: (0,6)
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denis23 [38]
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((2+9)/2, (4+4)/2)

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d^2=(4-4)^2+(9-2)^2

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d=7

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Earlier we found (h,k) to be (5.5, 4) and r=3.5 so our equation is:

(x-5.5)^2+(y-4)^2=3.5^2

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4 0
3 years ago
Mary can do a job in 80 minutes, Working with Jané, both can do the job in 30
LenKa [72]

Answer:

see below

Step-by-step explanation:

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3 0
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Arlecino [84]

Answer:

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3 years ago
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