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Katena32 [7]
2 years ago
12

PLS HELP!

Mathematics
1 answer:
makvit [3.9K]2 years ago
8 0

Answer:

5.81%

Step-by-step explanation:

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Which of the following could be used to calculate the area of a sector in the circle shown below
lara [203]

Answer:

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Step-by-step explanation:

Given:

Radius = r = 8 in

θ = 42°

To Find:

Area of Sector = ?

Solution:

We know that

\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}

Substituting the given values in the formula we get

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Which is the required Answer.

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

8 0
2 years ago
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Irina18 [472]

Answer:

30

Step-by-step explanation:

5 0
2 years ago
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A. Determine the value of an account in which a person invested $6000 for 12 years at an annual rate of 9% compounded annually (
Sliva [168]

Answer:

16875.98

Step-by-step explanation:

6000(1+(0.09/1)^1*12 = 16875.98

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2 years ago
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Answer:

B

Step-by-step explanation:

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The Internal Revenue Service (IRS) provides a toll-free help line for taxpayers to call in and get answers to questions as they
sukhopar [10]

Answer:

From the result of the one-tailed z-test, we can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Step-by-step explanation:

Sample size = 50

Mean waiting time = 13 minutes

Standard deviation = 11 minutes

We need to perform one hypothesis test that the actual mean waiting time turned out to be significantly less than the 15-minute claim made by the taxpayer advocate.

The null hypothesis would be that there is no significant difference.

H₀: μ₀ = 15 minutes

The alternative hypothesis would be that the mean waiting time is indeed significantly less than the 15-minute claim by the taxpayer advocate.

Hₐ: μ₀ < 15 minutes.

This is evidently a one tail hypothesis test (we're investigating only in one direction; less than the claim). Hence, we can use the z-test

z = (x - μ)/σₓ

σₓ = (σ/√n) = (11/√50) = 1.556

z = (13 - 15)/1.556 = - 1.29

Using the z-table at significance level of 0.05.

p-value = 1 - 0.9115 (from the z-tables)

p-value = 0.0885

Since the p-value is more than the significance level (0.0885 > 0.05), we do not reject the null hypothesis.

Hence, we accept the null hypothesis and can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Hope this Helps!!!

4 0
3 years ago
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