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inysia [295]
3 years ago
5

Write an expression to match the phrase 15 subtracted from the quotient of 40 and 2

Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

(40/2)-15

Step-by-step explanation:

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PLS NEED HELP WITH 3 AND 4
Rainbow [258]

Answer:

the first one is 62 and the second one

Step-by-step explanation:

i dont know the second one

3 0
3 years ago
An EPA contractor needs to test the concentration of a substance in ten samples of the ground water. Seventy samples were
olga55 [171]

Answer:

Systematic sampling

Step-by-step explanation:

An EPA contractor needing to test the concentration of a substance in ten samples out seventy samples provided form a single source at regular time intervals.

For the contractor to effectively carry out the testing he has to employ a Non-probability system of sampling which is called Systematic sampling, because in systematic sampling we can assume the population size (x ) which in this case is 70 and the sample size( n ) to be 10

He will have to select ;  ( x / n )^th of the sampling frame for best results

7 0
3 years ago
What is the inverse of the function?<br> f(x) = 1/3x-5
OlgaM077 [116]

Answer:

        -1

       f   (x) = -3(x + 5)

Step-by-step explanation:

1)  in f(x) = 1/3x-5, replace f(x)= with y= as follows:  y = (1/3)x - 5

2) interchange x and y, obtaining:  x = (1/3)y - 5

3) solve this result for y:  (1/3)y = -x - 5, or -(x + 5).  Next, multiply both sides by                        3 to eliminate the fraction (1/3):  y = -3(x + 5)

4)  replace y with the symbol for "inverse of f(x);

        -1

       f   (x) = -3(x + 5)

5 0
3 years ago
Find midpoint of CD C=(10,-1)and D=(6,3)
antoniya [11.8K]

Answer:

(8,1)

Step-by-step explanation:

The x coordinate of the midpoint is

(10+6)/2 = 16/2  =8

The y coordinate  of the midpoint is

(-1+3)/2 = 2/2 =1

The midpoint is (8,1)

6 0
3 years ago
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
dmitriy555 [2]
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0                              (quadratic equation)

2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0                                          (not a quadratic equation)

5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4                                      (quadratic equation)

5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0                    (not a quadratic equation)

Therefore, options a and c can be solved using the quadratic formula.
3 0
3 years ago
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