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nordsb [41]
4 years ago
8

Mike is building a new deck in his backyard with the dimensions shown in the diagram. He needs to determine how many square feet

of lumber needs to be purchased. Find the total area of the deck.
A) 25 ft2
B) 50 ft2
C) 75 ft2
D) 125 ft2
Mathematics
2 answers:
timofeeve [1]4 years ago
8 0

Answer:

The answer is D. 125

Step-by-step explanation:

arlik [135]4 years ago
5 0

Answer:

to answer this question there needs to be the diagram attached. assuming the deck is a rectangle, multiply length times width to find your answer.

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What is an equation in slope-intercept form for the line that passes through the points (1,-3) and (3,1)
sergey [27]

Step-by-step explanation:

Hey there!

<u>Note</u><u>:</u><u> </u><u>Use</u><u> </u><u>double</u><u> point</u><u> formula</u><u> for</u><u> finding</u><u> </u><u>the</u><u> eqaution</u><u> which</u><u> </u><u>pass</u><u>es</u><u> through</u><u> </u><u>two</u><u> </u><u>points</u><u>.</u>

Given;

The points are; (1,-3) and (3,1).

<u>Use</u><u> </u><u>dou</u><u>ble</u><u> point</u><u> formula</u><u>.</u>

<u>(y - y1) =  \frac{y2 - y1}{x2 - x2} (y - y1)</u>

<u>Put</u><u> </u><u>all</u><u> </u><u>values</u><u>.</u>

<u>(y  + 3) =  \frac{1  + 3}{3 - 1} (x - 1)</u>

<u>Simpl</u><u>ify</u><u> it</u><u>.</u>

<u>(y + 3) =  \frac{4}{2} (x - 1)</u>

<u>y + 3 = 2(x - 1)</u>

<u>y + 3 = 2x - 2</u>

<u>y  = 2x - 2 - 3</u>

<u>y = 2x - 5</u>

Therefore, the eqaution is y = 2x-5.

Alternative:

<u>Steps</u><u>:</u>

  • Find slope using slope formula and use one point formula.
  • Simplify in the form of y = mx+c form.

Formula:

  • Slope = (y2-y1)/(x2-x1)
  • One point formula= (y-y1)= m(x-x1)

The points are; (1,-3) and (3,1).

Now;

Slope= (1- (-3))/(3-1)

= (1+3)/2

= 2

Again;

Using one-point formula.

(y+3) = 2(x-1)

y+3= 2x-2

y = 2x -5

Therefore, the equation is y = 2x-5.

(You can follow up any method you want)

<em><u>Hop</u></em><em><u>e</u></em><em><u> it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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