Could you repost the pic it is a bit hard to read
Given : −3 + 5 + 6g = 11 − 3g
To find : The variable g
Solution:
Isolate and solve for the variable g in the equation −3 + 5 + 6g = 11 − 3g
<u>Steps:</u>
−3 + 5 + 6g = 11 − 3g
2 + 6g = 11 − 3g
6g = −3g + 9
9g = 9
g = 1
Hence,
Answer: g = 1
Answer:Use a calculator
Explanation:it’s easier
Answer:
h = -2
Step-by-step explanation:
subtract 5 from both sides (5-8h-5=21-5)
simplify (-8h=16)
divide both sides by -8 (both -8's cancel, leaving 16/-8 which is -2.)
Answer:
a) <em>t</em> ≥ 5
b) (see below)
Step-by-step explanation:
First, make note of the info you are given and what you're trying to do:
- at midnight, 5°C
- drops consistently 2°C per hour
- finding <em>t</em>
- <em>t </em>= # of hours past midnight when temp. was past -4°C
- put <em>t</em> on a number line
So, first, you need to find the first point at when the temperature goes past -4°C. Notice that the question is asking for past -4°C, not -4°C<em> and</em> past. This means we're not including -4°C.
Every hour, we're dropping by 2°C. You can draw a visual to better understand the situation. See the image below.
So we know that starting from 5 am, we are lower than -4°C.
This is 5 hours from midnight.
So <em>t</em> ≥ 5. This means that the number of hours past midnight when the temperature was colder than -4°C was 5 or more hours.
On the number line, draw a circle on 5 (between 4 and 6), but shade it in because it includes 5. Then, shade or highlight to the right of that circle to the end of the number line.
This shows that <em>t</em> is equal to or greater than 5.