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2 years ago

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A car dealership advertises a used Toyota Tercel for only $400 down and $170 per month for 4 years. What is the total cost of th

e car? Given answer: The total cost of the car is $8,016.

1 answer:

erica [24]2 years ago

7 0

Answer:

the answer is wrong!! is 8,560 total cost

Step-by-step explanation:

170x48(4 years) = 8,160

8,160+400(down) = 8,560 total cost

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Which of these numbers is a common factor of 54 and 81? 54 = 2 x 3 x 3 x 3 81 = 3 x 3 x 3 x 3 A) 2 B) 6 C) 9 D) 18

stealth61 [152]

Answer:

C) 9

Step-by-step explanation:

54 = 2 x 3 x 3 x 3

81 = 3 x 3 x 3 x 3

common factor of 54 and 81 = 3 x 3 = 9

Answer: 9

6 0

2 years ago

Read 2 more answers

Chin-li is building a brick wall along the front of his property. The wall will have 15 rows of bricks, with 32 bricks in each r

Finger [1]

Answer:

<h3>The solution is 480 bricks.</h3>

Step-by-step explanation:

We are given that number of rows of bricks in a wall = 15 rows.

Number of bricks in a row = 32 bricks.

In order to find the total number of bricks, we need to multiply number of rows with number of bricks in a row.

Total number of bricks in 15 rows = 15 × 32 = 480 bricks.

Therefore, will Chin-li will need 480 bricks.

<h3>The solution is 480 bricks.</h3>

3 0

2 years ago

storchak [24]

Answer:

2nd option will be the answer (y=4x²+48x+146)

Step-by-step explanation:

y=4(x+6)²+2

y=4(x²+2*x*6+6²)+2 [(a+b)²=a²+2ab+b²]

y=4(x²+12x+36)+2

y=4(x²)+4(12x)+4(36)+2

y=4x²+48x+144+2

y=4x²+48x+146

5 0

2 years ago

Simplify each using positive exponents only: questions on image

Juliette [100K]

Answer:

16) 8/X

19) 16x^8

22)81x^8

5 0

2 years ago

Trucks in a delivery fleet travel a mean of 110 miles per day with a standard deviation of 38 miles per day. The mileage per day

Montano1993 [528]

Answer: 0.1824

Step-by-step explanation:

Given : The mileage per day is distributed normally with

Mean : $\mu=110\text{ miles per day}$

Standard deviation : $\sigma=38\text{ miles per day}$

Let X be the random variable that represents the distance traveled by truck in one day .

Now, calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 132 miles per day.

$z=\dfrac{132-110}{38}\approx0.58$

For x= 159 miles per day.

$z=\dfrac{159-110}{38}\approx1.29$

Now by using standard normal distribution table, the probability that a truck drives between 132 and 159 miles in a day will be :-

$P(132$

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824

6 0

2 years ago