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2 years ago

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1 answer:

worty [1.4K]2 years ago

4 0

No change in area

Step-by-step explanation:

The area is 60 square feet for both rectangles.

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HELP PLEASEE ITS DUE TODAYYY !!

zimovet [89]

Answer:

there would be 55 different combinations if there were 9 painting and there would be 49 different combinations if there were 8 paintings. i don't know what the first question means

8 0

3 years ago

. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar

yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

$K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455$

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

$\frac{270}{455}=0.5934=59.34\%$

(b)

The probability of selecting three 40-W bulbs is

$\frac{4*3*2}{455}=0.0527=5.27\%$

The probability of selecting three 60-W bulbs is

$\frac{5*4*3}{455}=0.1318=13.18\%$

The probability of selecting three 75-W bulbs is

$\frac{6*5*4}{455}=0.2637=26.37\%$

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

$\frac{6*5*4}{455}=0.2637=26.37\%$

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is $\frac{9}{15}=0.6$

Since there are no replacement, the probability of taking a second non 75-W bulb is now $\frac{8}{14}=0.5714$

Following this procedure 5 times, we find the probabilities

$\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}$

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0

3 years ago

Car = V-8 sedan Years driven = first through third Miles driven = 14,000 miles each year In dollars and cents, the total project

saveliy_v [14]

Answer:

609

Step-by-step explanation:

5 0

3 years ago

Use the functions f(x) = 4x² + 3 and g(x) = 3x + 2 to evaluate the following.

natita [175]

Answer:

Step-by-step explanation:

f(-2)= 4(-2)^2 + 3 = 4(4) + 3 = 16 + 3 = 19

g(19) = 3(19) + 2 = 57 + 2 = 59

g(-2)= 3(-2) + 2 = -6 + 2 = -4

f(-4)= 4(-4)^2 + 3 = 64 + 3 = 67

7 0

3 years ago

Read 2 more answers

What’s the solution of y= 3x-1 and y= 3x+4

julia-pushkina [17]

Step-by-step explanation:

solution ? you mean where both lines cross each other ?

these are 2 parallel lines (same slope, but different y-intercept), so they never cross each other.

there is no solution.

formally :

3x - 1 = 3x + 4

-1 = 4

this is wrong. therefore there is no solution.

3 0

2 years ago