Answer:
a =17.08
b = 16.97
Step-by-step explanation:
What are the values of a and b?
Using pythagoras therem';
Hyp^2 = opp^2 + adj^2
Get the value of b;
18^2 = b^2 + 6^2
324 = b^2 + 36
b^2 = 324 - 36
b^2 = 288
b = √288
b = 16.97
Get the value of a;
b^2 + 2^2 = a^2
288 + 4 = a^2
292 = a^2
a^2 = 292
a = √292
a= 17.09
Answer:
t = 9.08 sec
Explanation :
This requires the use of the kinematic equations.
u = initial velocity = 21.8 m/s
v = final velocity = 0
t = time = what we're trying to find.
So we use the equation that relates d, u, v and t. This is
d = distance = 99m
d = 
and since v = 0 this reduces to d = 
which rearranges to t =
t =
=9.08 seconds
t = 9.08 sec
Answer:
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Step-by-step explanation:
Create a graph and plug in the information you can use desmos or look up other work time check in sites its much easier
V = by
Solve for b.
Divide both sides by y to isolate b.
b=