4 years ago

Need help on the answer

Mathematics

2 answers:

Wittaler [7]4 years ago

6 0

The answer is the 4th option

Serjik [45]4 years ago

4 0

Answer:

its the 4th one

Step-by-step explanation:

you go up by 4 and right by 3

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4 years ago

Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.

Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

$\frac{sinA}{a}=\frac{sinB}{b}$

$\frac{sin30}{4}=\frac{sinB}{6}$

$sinB=0.75$

$angle B = 48.6$

Another angle will be

$angle B' = 180-48.6 = 131.4$

considering angle B, angle C = $180 - (48.6+30)=101.4$

considering angle B', angle C' = $180-(131.4+30)=18.6$

$\frac{sinA}{a}=\frac{sinC}{c}$

$\frac{sin30}{4}=\frac{sin101.4}{c}$

$c = 7.84$

Similarly, finding c'

$\frac{sinA}{a}=\frac{sinC'}{c'}$

$\frac{sin30}{4}=\frac{sin18.6}{c'}$

$c'=2.55$

Hence two triangles are possible with below details: : Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

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3 years ago