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Airida [17]
4 years ago
9

F(x)=1/x and g(x)=x^2-6x what 2 numbers are not in the domain of f times g

Mathematics
1 answer:
Flura [38]4 years ago
3 0
F(x) = 1/x
g(x) = x^2 - 6x
(f * g)(x) = 1/x(x^2 - 6x) = x - 6

The domain of (f * g)(x) is all real numbers.
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Y-3=-3y-43 how would i solve?​
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Answer: y−3=−3y−43

Step 1: Add 3y to both sides.

y−3+3y=−3y−43+3y

4y−3=−43

Step 2: Add 3 to both sides.

4y−3+3=−43+3

4y=−40

Step 3: Divide both sides by 4.

4y

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y=−10

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y=−10

Step-by-step explanation: brainliest:)

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Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

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|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

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(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
3 years ago
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