Ask question

Ask question

All categories

3 years ago

11

A pole that is 3.5m tall casts a shadow that is 1.7m long. At the same time, a nearby building casts a shadow that is 36.5m long

. How tall is the building? Round your answer to the nearest meter.

1 answer:

GalinKa [24]3 years ago

5 0

1.)Convert into Proportion: 3.5/1.7=x/36.5
2.)Cross Multiply: 1.7x=127.75
3.)Simplify and Solve: x=75.14

x=75.14m tall

You might be interested in

For the graph x = -3 find the slope of a line that is parallel to it.

slava [35]

We have that

the slope of the line that is parallel to x=-3 is classified as undefined.

<span>let's check the answer
</span><span>1) take any two points of the line x = -3
</span>point A (-3,0) point B (-3,5)
2) find the slope of the line x=-3
m=(5-0)/(-3+3)=5/0----------> is undefined

the answer is the option undefined

5 0

3 years ago

A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.

gizmo_the_mogwai [7]

Answer:

$z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280$

$p_v =P(z>0.280)=0.390$

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=3.1$ represent the sample mean

$\sigma=\sqrt{6}$ represent the sample standard deviation for the sample

$n=47$ sample size

$\mu_o =3$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:

Null hypothesis: $\mu \leq 3$

Alternative hypothesis: $\mu > 3$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280$

P-value

Since is a one side test the p value would be:

$p_v =P(z>0.280)=0.390$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.

3 0

3 years ago

Help please? :))))))))))))

Ivan

A. 4times y+2 b. 5-x times 3 times y c. -2 times y-3 d. -7 times 4+x e. 16 times x -8 divided by 4 f. 1 divided by 3 times 2 times x +3

sorry I tried to make it out the best that I could I don't have all the symbols so I just wrote out the divide and multiply parts

5 0

3 years ago

Read 2 more answers

An experiment consists of tossing a die and then flipping a coin once if the number on the die is even. If the number on the die

Dahasolnce [82]

Answer:

Kindly check attached picture and explanation

Step-by-step explanation:

A.) The tree diagram is attached in the picture below.

B.) Number less than 3 :

Event A:

A = {1HH, 1HT, 1TT, 1TH, 2H, 2T}

C.)

Event B:

B = {1TT, 3TT, 5TT}

D.)

Event C:

C = {1HT, 1TH, 3HT,3TH,5HT, 5TH}

E.)

A' = Elements not in A = number ≥ 3

A' = {3HH,3HT, 3TT, 3TH, 4H, 4T, 5HH, 5HT, 5TH, 5TT, 6H, 6T}

Question f and G are not well formatted ;

h. Check attached picture

I) i. Are A and B mutually exclusive? Are A and C mutually exclusive? Are B and C mutually exclusive?

A and B are mutually exclusive if AnB = ∅

Check :

AnB = {1TT}

Hence, A and B are not mutually exclusive

A and C

AnC = {1HT, 1TH}

A and C are not mutually exclusive.

B and C

BnC = ∅

B and C are mutually exclusive

4 0

2 years ago

there are 30 flowers in a vase 2.5 of flowers are roses. 1/6 of the flowers are daisies. the rest of the flowers are carnations.

tekilochka [14]

Answer:

13 carnations

Step-by-step explanation:

Assuming you meant 2/5 because 2.5 would mean there are more roses in the vase than there are flowers in the vase, heres how to solve this.

Understanding

Each fraction is referring to "flowers" not "remaining flowers" and as such each time we will be comparing to the total.

2/5 of the total flowers are roses. This is written in words as for every 5 flowers two are roses, which means we will multiply 2 by how many sets of five we have in 30 flowers.

(30/5) x 2 =

(6) x 2 = 12 roses

Though with fractions its written as 30/1*2/5 which is the same as (30 x 2)/5

60/5 = 12 roses

Following this logic for every 6 flowers one is a daisy.

30/1 * 1/6 = (30 x 1)/6 = 30/6 = 5 daisies

Because the rest are carnations we want to subtract the amount of daisies and roses from the total amount of flowers to find the remaining flowers.

30 - 5 - 12 = 13 carnations

Hope this helps,

8 0

3 years ago