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AVprozaik [17]
3 years ago
6

Suppose that a company's sales were $1,000,000 6 years ago and are $9,000,000 at the end of the 6 years. Find the geometric mean

growth rate of sales. (Round your answer to 4 decimal places.)

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

The geometric mean growth rate of sales is 1.4422.

Step-by-step explanation:

We have two sales values, one from 6 years ago and the other from now.

We have to calculate the geometric growth rate of sales.

We have:

y(-6)=1,000,000\\\\y(0)=9,000,000

We can write the relation between these two values as:

y(0)=y(-6)k^{0-(-6)}\\\\9,000,000=1,000,000k^6\\\\k^6=9\\\\k=9^{1/6}= 1.4422

The geometric mean growth rate of sales is 1.4422.

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Monica worked 3.5 hours and is paid $10 per hour. How much did she make in 3.5 hours?
marysya [2.9K]

Answer:

She would make $35.

Step-by-step explanation:

If you do 10 x 3.5, you will get the answer of $35.

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3 years ago
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In a 3/4 mile relay race, each runner runs 1/16 mile. How many runners are in the race?
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Twelve runners because if you take three-fourths times four you will get twelve-sixteenths. and each runner runs one-sixteenth so it is twelve.
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8 students in the play, 20 are not
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Chase is making calzones that require 2 3/4 pounds of beef. He only has 1,1/6 pound left. How much more does he need?
Dovator [93]
Here is the solution of the given problem above.
Firstly, to make the solution easier, let us convert the mixed fractions.
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1 1/6 is 7/6 (Pounds of beef available)
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6 0
3 years ago
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Humood's house is (-5,7)
grin007 [14]

The distance from Humood's house to the school is 500m

<h3>How to determine the distance from Humood's house to the school?</h3>

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2

Substitute the known values in the above equation

d = \sqrt{(-5 - 3)^2 + (7 - 1)^2

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m

Read more about distance at

brainly.com/question/1872885

#SPJ1

8 0
1 year ago
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