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natka813 [3]
3 years ago
8

0.45 as fraction in lowest term

Mathematics
1 answer:
Brut [27]3 years ago
4 0
<span>9⁄20</span><span>  




Best of luck

Hope I helped :)</span>
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A second number is 9 times a first number. A third number is 100 more than the first number. If the sum the three numbers is 694
Ierofanga [76]

Answer:

54, 486, 154

Step-by-step explanation:

x+9x+100+x= 694

11x= 694-100

11x=594

x= 54

54×9=486

54+100= 154

54+486+154=694.

7 0
3 years ago
Choose the method to solve the problem below: There are members on a board of directors. If they must form a subcommittee of mem
shepuryov [24]

Answer:

b. 56

Step-by-step explanation:

Please consider the complete question.

There are 8 members on a board of directors. If they must form a subcommittee of 3 members, how many different subcommittees are possible?

We will use combinations for solve our given problem.

^nC_r=\frac{n!}{r!(n-r)!}, where,

n = Number of total items,

r = Items being chosen at a time.

For our given scenario n=8 and r=3.

^8C_3=\frac{8!}{3!(8-3)!}

^8C_3=\frac{8!}{3!\cdot 5!}

^8C_3=\frac{8\cdot7\cdot6\cdot5!}{3\cdot2\cdot1\cdot 5!}

^8C_3=8\cdot7

^8C_3=56

Therefore, 56 different subcommittees are possible and option 'b' is the correct choice.

4 0
3 years ago
For each situation, determine the slope and y-intercept if the graph of the equation that describes the situation.
Serggg [28]

So the slope is 200 as he gains $200 each day

and the y intercept is 500, since he receives the $500 only once

y = 200x + 500

5 0
3 years ago
Which category of galaxy does not have a distinctive shape
sweet [91]
I believe an irregular galaxy is what it's called
6 0
4 years ago
find the value of a and b for which the system of equations has infinitely many solutions : 2x + 3y = 7 ; (a-b)x + (a+b)y = 3a +
hodyreva [135]

Answer:

a= 5    and   b=1

Step-by-step explanation:

To solve, we will follow the steps below:

2x + 3y = 7

(a-b)x + (a+b)y = 3a + b - 2​

We should note that since it has infinitely many solutions then,

\frac{a_{1} }{a_{2} }   =  \frac{b_{1} }{b_{2} }  = \frac{c_{1} }{c_{2} }

Hence

2/a-b  =  3/a+b   =     7/3a +b-2

2/a-b  =  3/a+b

cross-multiply

3(a-b) = 2( a+b)

open the bracket

3a - 3b = 2a + 2b

collect like term

3a - 2a = 2b + 3b

a = 5b  -------------------------------------------(1)

Similarly

3/a+b   =     7/3a +b-2

cross-multiply

7(a+b)  = 3(3a+b -2)

7a + 7b = 9a + 3b -6

take all the variables to the left-hand side of the equation

7a - 9a+ 7b-3b =   -6

-2a + 4b = -6 ---------------------------------(2)

but a = 5b

substitute a= 5b in equation (2)   and solve for b

-2(5) + 4b = -6

-10  +  4b  = -6

add 10 to both-side of the equation

-10  + 10+ 4b  = -6+10

4b = 4

divide both-side of the equation by 4

b = 1

substitute b= 1 in equation (1)

a = 5b

a =5(1)

a=5

Therefore,   a= 5    and   b=1

8 0
4 years ago
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