Answer:
the greatest common factor is 6
Robert is not correct because in order for it to be supplementary the angles have to be consecutive interior
Eliminate the exponent
2^3=8
9^3=729
The simplified answer would be 8/729.
Hope this helps!
For the answer to the question above, <span>Well, first let us put up a functional equation. </span>
<span>Since this is an exponential function, it'll be: f(t)=54,000*1.03^t </span>
<span>But we want to know how many wolves there were 10 years ago. </span>
<span>For that, we simply "turn time around", as in: f(t)=54,00*1.03^-t </span>
<span>This displays a decreasing number of wolves, as you turn back time. </span>
<span>Now we simply calculate 54,000*1.03^-10 </span>
<span>which is approximately 40,200?</span>
Answer:
- y = 50·3^x
- (2, 450), (3, 1350), (4, 4050), (5, 12150)
Step-by-step explanation:
The problem statement tells you each observed count is 3 times the last one.
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Expressed as an exponential function with an initial value of 50 and a growth factor of 3, the formula is ...
y = (initial value)×(growth factor)^x
y = 50·3^x
